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inn [45]
3 years ago
10

A school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second grade travel

in the bus. How many ways can the students be seated if all the first-grade students occupy the first 3 rows?
A. 25P20
B. 5P5 × 20P15
C. 15C15 × 10C5
D. 15P15 × 10P5
E. 15P15 × 10C5
Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0

Answer:

b

Step-by-step explanation:


tatuchka [14]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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two numbered 1 to 6 dice are thrown together and their scores are added. the probability that the sum will be 4 is?​
natulia [17]

Answer:

Pr = \frac{3}{36}

Step-by-step explanation:

Given

2 number die

Required

P(Sum = 4)

The sample space of 2 die is:

S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6), (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6), (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6), (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

n(S)= 36

The pairs that adds up to 4 are:

Sum(4) = \{(1,3), (2,2),(3,1)\}

n(Sum)  =3

So, the probability is:

Pr = \frac{n(Sum)}{n(S)}

Pr = \frac{3}{36}

5 0
2 years ago
(-5i)(-3i) ASAP!!! Brainlest <br> Solving quadratic equations<br> Simply
yKpoI14uk [10]

Answer:

15i^2

Step-by-step explanation:

a negative times a positive is a negative and a negative times a negative is positive

-5×-3=15 and i×i=i^2

4 0
2 years ago
I DONT UNDERSTAND HELP <br> Find the values of the variables<br><br> (Simplify your answers )
SVETLANKA909090 [29]

Answer:

x=88 (alternative angles)

y=31 each

v=41 (alternative angles)

w=20 (alternative angles)

Step-by-step explanation:

for y:

we add all the angles got therefore,

20+41+88+y+20+41+88+y=360(because total angle in a quadilateral is 360°)

298+2y=360

2y=360-298

2y=62

therefore y=62/2=31° for each y

4 0
2 years ago
PLZ HELP WILL GIVE BRAINLIEST WORTH 10 PTS THX!!
antiseptic1488 [7]

Answer:

  64/49

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

  a^0 = 1

_____

Using these rules, we can simplify the given expression to ...

  \left(\dfrac{8\cdot 4\cdot 2}{8\cdot 7}\right)^2\times\left(\dfrac{8^0}{7^{-3}}\right)^3\times 7^{-9}\\\\=\dfrac{8^2}{7^2}\times(8^{0\cdot 3}\cdot 7^{3\cdot 3})\times 7^{-9}\\\\=\dfrac{64}{49}\times(8^07^{9-9})=\boxed{\dfrac{64}{49}}

6 0
3 years ago
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If five times a number plus two is 17 what is the number? A. 3 B. 2 C. 7 D. 5
VLD [36.1K]
5*3+2=17 it's A, 3 in this equation.
3 0
3 years ago
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