Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
542,591,806.5
.............................
Answer:
The answer would be (-7,3)
Step-by-step explanation:
Answer: "
267.95 m³ " .
______________________________________________________Explanation:________________________________________________________V = (4/3) *
* r³ ;
Given: diameter, "d" = "8 m" ;
radius, "r" = 8 m / 2 = 4 m "
V = (4/3) *
* r³
V = (4/3) *
*(4m)³
V = (4/3) * (3.14) * 4³ * m³ ;
V = (4/3) * (3.14) * (4*4*4) * m³ ;
V = (4/3) * (3.14) * (64) * m³ ;
V = 267.9466666666666667 m³ ;
round to: "
267.95 m³ " .
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