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Anastaziya [24]

4 years ago

15

The scissor lift is a device that can lower and raise a platform. the scissor lift can raise the platform at a rate of 2.0 inche

s per second after t seconds is given by H=2.0t +35. after how many minutes will the lift be at least 50 feet off the ground

1 answer:

Svetradugi [14.3K]4 years ago

3 0

Answer:

i thank it is 25 seconds.

Step-by-step explanation:

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The base of a triangle is 8 1 3 meters and the height of the triangle is the fourth root of 16 meters meters. What is the area o

just olya [345]

Answer:

The area of triangle is $8 \frac{1}{3}\ m^{2}$

Step-by-step explanation:

we know that

The area of a triangle is equal to

A=(1/2)bh

we have

b=8 1/3 m

convert to an improper fraction

8 1/3 m=(8*3+1)/3=25/3 m

The fourth root of 16 is equal to 2

$\sqrt[4]{16}=(2^{4})^{1/4}=2$

so

h=2 m

substitute

$A=(1/2)(25/3)2=25/3\ m^{2}$

convert to mixed number

$25/3=(24/3)+(1/3)=8+1/3=8 \frac{1}{3}\ m^{2}$

5 0

3 years ago

There were 8 red cars and 12 blue cars in the parking lot what is the ratio of the number of red cars to number of blue cars

salantis [7]

Answer:

2 : 3

Step-by-step explanation:

<em>Hello fellow human!</em>

red : blue - 8 : 12

The ratio is divisible by 4 - (8/4) = 2 ; (12/4) = 3

Hence, 2 : 3

8 0

2 years ago

PLEASE HELPPPPPPpppppppppppppppppppppp

Usimov [2.4K]

Its 4 by the way cause it is

6 0

3 years ago

A bag has 1 red marble, 4 blue marbles, and 3 green marbles. Peter draws a marble randomly from the bag, replaces it, and then d

love history [14]

I think it's 50%, tell me if my answer was right please

5 0

3 years ago

Can you help me with number 6? <br> Confused abit <br> Please

Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.

To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.

First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is

$\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}$

Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is

$\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}$

Third question:

To get exactly one six, it can either be the first, second or third roll.

In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.

In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus

$\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}$

And since there are three of these combinations, The answer is

$3\frac{5^2}{6^3}$

Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is

$1 - \frac{5^3}{6^3}$

4 0

3 years ago