Let the number of Go-go scooter to be produced be x and that of Whip scooter y, then
Maximize: R = 3200x + 5000y
subject to:
x + y ≤ 120
3x + 6y ≤ 600
The corner points of the constraints are (0, 0), (0, 100), (40, 80), (120, 0)
For (0, 0): R = 0
For (0, 100): R = 3200(0) + 5000(100) = 500,000
For (40, 80): R = 3200(40) + 5000(80) = 528,000
For (120, 0): R = 3200(120) + 5000(0) = 384,000
Therefore, for maximum revenue, they should produce 40 Go-go scooters and 80 Whip scooters.
Answer:
In terms of %, it's 20%.
Step-by-step explanation:
Used an ROI calculator:
Answer:
-1
Step-by-step explanation:
Answer:
the probability of it being a yellow ticket is 6/11 and the probability of it being an odd numbered ticket is also 6/11. i dont know how you would do one fraction for both the yellow and the odd numbered tickets together but this is what i got.
Step-by-step explanation:
So I have the same problem with you