The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
Learn to solve more word problems here: brainly.com/question/2610134
#SPJ4
Answer:
0.002M
Step-by-step explanation:
2.7= -log(H^+)
-2.7=log(H^+)
10^-2.7 M=H^+
0.0002M=H^+
Answer:
8 months
Step-by-step explanation:
194-3m = 217-6m
3m = 23
m=7.666666..... (8 months
Answer: Hope this helps.
13, 7
Step-by-step explanation:
Number one is 13
Number two is 7
Well 7 x 2 = 14, 14-1 = 7, and 7+13 = 20 making the answers true.
I figured out this number by eliminating numbers, I started with 5, ended with 8 to make a range of the possible numbers. Since 5 was too low and 8 was too high I knew the number had to be either 6 or 7, so I did 7 and I got the answer.
