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Nana76 [90]
3 years ago
14

Write in simplest form

Mathematics
1 answer:
SashulF [63]3 years ago
3 0

Answer:

1 1/3 is your simplest form

Step-by-step explanation:

Remember to follow PEMDAS (Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction).

First, note the division. To solve division with fractions, you must take the following steps:

Take the fraction in the denominator (or the one directly to the right of the division sign), flip the fraction, and change the division into multiplication:

(-1/3)/(6/7) = (-1/3) x (7/3)

Simplify.

-1 x 7 = -7

3 x 3 = 9

5/9 - (-7/9)

combine like terms:

5/9 - (-7/9) = 5/9 + 7/9 = 12/9

Simplify the fraction.

12/9 = 9/9 + 3/9

9/9 = 1 ; (3/9)/(3/3) = 1/3

1 1/3 is your simplest form.

~

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AB<br> Round your answer to the nearest hundredth.<br> С<br> 4<br> A<br> 25°<br> ?<br> B
Nana76 [90]

Answer:

AB ≈ 4.41

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos25° = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{4}{AB} ( multiply both sides by AB )

AB × cos25° = 4 ( divide both sides by cos25° )

AB = \frac{4}{cos25} ≈ 4.41 ( to the nearest hundredth )

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3 years ago
Express in an inequality that -8.5C is warmer than -15C
ExtremeBDS [4]
Hello!

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3 years ago
The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth
Bess [88]

Answer:

Perimeter of given regular hexagon is <em>48.5 ft</em>.

Step-by-step explanation:

Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.

<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE are equilateral \triangle s.

Area of an equilateral \triangle is defined as :

\dfrac{\sqrt{3}}{4} \times a^{2}

Where <em>a </em>is the side of \triangle.

Area of hexagon = 6 \times \dfrac{\sqrt{3}}{4}\times a^{2}

We are given that area of hexagon = 169.74 ft^{2}

Let <em>s </em>be the side of hexagon.

\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft

A regular Hexagon is made up of 6 equal sides, so

Perimeter of a regular hexagon = 6 \times side

Perimeter = 6 \times 8.08

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So, perimeter of given regular hexagon is 48.5 ft.

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PLZ help its due at 11:59
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6 0
4 years ago
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