The width would be 1 inch.
Given: L = length = 5W; P = perimeter = 2(L+W) = 12 inches
Required: W = width;
Formula: P=2(L+W)
Solution:
12 in = 2 (L + W)
6 in = L + W
6 in = 5W + W
6 in = 6W
1 in = W
Cross check:
P = 2(L + W)
12 in = 2(5 in + 1 in)
12 in = 2(6 in)
12 in = 12 in
Answer:
Step-by-step explanation:
Answer:
Proof of alternate exterior angles theorem. Consider the diagram above. The two lines are parallel.
Step-by-step i took the test but i guess i will show u % of the x and y quardernates and then x5 andd 6
What you’re doing is breaking it down into its parts and writing it into an equation that way long hand.
3 + .4 + .00 + .005
Here's the one with whole numbers:
[8] [1] [6]
[3] [5] [7]
[4] [9] [2]
For the one with polynomials, all you have to do it pick any weird number
you want for 'x', and then translate the whole numbers into expressions
with 'x' in them.
For example, if you say that 'x' is 1.6 . . . just a wild pick. Then ...
1 = x - 0.6
2 = x + 0.4
3 = 2x - 0.2
and so forth, and you could fill these into the second magic square
in place of the whole numbers.
Or if you don't want to mess with all the decimals, then just pick
a whole number for 'x'. I don't know ... maybe ' 4 '. Then ...
1 = x -3
2 = -x + 6
3 = (1/2)x + 1
and so forth. You just pick any old number you want for 'x',
and then make up expressions with it to substitute for all the
whole numbers in the first magic square.