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Shkiper50 [21]
3 years ago
13

A rectangle has the length that is five times longer than it’s width. If the perimeter of the rectangle is 12 inches, whats the

width?
Mathematics
1 answer:
NemiM [27]3 years ago
7 0
The width would be 1 inch.

Given: L = length = 5W; P = perimeter = 2(L+W) = 12 inches
Required: W = width; 
Formula: P=2(L+W) 
Solution:
              12 in = 2 (L + W)
              6 in = L + W
              6 in = 5W + W
              6 in = 6W
              1 in = W
Cross check:
              P = 2(L + W)
              12 in = 2(5 in + 1 in)
              12 in = 2(6 in)
              12 in = 12 in
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Steps:
Percent Error =
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Vtrue
=
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246.9
=
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saveliy_v [14]

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A $250,000 home loan is used to purchase a house. The loan is for 30 years and has a 5.4% APR. Use the amortization formula to d
wlad13 [49]
\bf ~~~~~~~~~~~~ \textit{Amortized Loan Value}
\\\\
pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right]
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~~~~~~
\begin{cases}
P=
\begin{array}{llll}
\textit{original amount deposited}\\
\end{array}\to &250000\\
pymt=\textit{periodic payments}\\
r=rate\to 5.4\%\to \frac{5.4}{100}\to &0.054\\
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\begin{array}{llll}
\textit{times it compounds per year}\\
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\end{array}\to &12\\
t=years\to &30
\end{cases}


\bf pymt=250000\left[ \cfrac{\frac{0.054}{12}}{1-\left( 1+ \frac{0.054}{12}\right)^{-12\cdot 30}} \right]
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