Answer:
(-2, 5)
Step-by-step explanation:
I will assume that your system is
y = -4x - 3
y = -2x + 1
Multiplying the second equation by -2 results in
y = -4x - 3
-2y = 4x - 2
combining these two equations eliminates x temporarily:
-y = -5, so that y must be 5.
Substituting 5 for y in the second equation, we get:
5 = -2x + 1, or
4 = -2x, which results in x = -2
and so the solution is (-2, 5)
If you don’t have any of the angles, you would use the law of cosines to find an angle.
Answer:
37 and 26
Step-by-step explanation:
Let the bigger number be x and the smaller number be y.
Then the two numbers total 63 will give us:
y+x=63------>eqn1
The two numbers have a difference of 11.
y-x=11------->eqn2
We add equations 1 and 2 to obtain:
2y=74
Divide both sides to get:
y=37
Put y=37 into eqn2 to get:
37-x=11
x=37-11
x=26
This larger number is 37 and the smaller number is 26
Answer:
8
Step-by-step explanation:
eight more anakd;odslakhas sfjjjsjas
You are correct in thinking that the columns of the first matrix must match with the rows of the second matrix.
So for example, we can multiply a 1 x 5 matrix with a 5 x 7 matrix. The two matching '5's are directly what make multiplication possible in this case. For your problem, the first two '3's match and multiplication is possible.
The rows of the first matrix don't need to match with the columns of the second matrix.
