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olga nikolaevna [1]
3 years ago
5

Write the fraction 2/7 as an equivalent fraction with the given denominator 28.

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

8/28

Step-by-step explanation:

2/7  = ?/28

Well we have both of the denominators, and all they did was multiply the denominator of "7" by 4 to get "28" as the other denominator, so now all we have to do is multiply the first numerator by 4 to get the equivalent fraction.

2*4/7*4 = ?/28

8/28 = ?/28

The given numerator will be 8.

2/7 is equivalent to 8/28

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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Soloha48 [4]

Answer:

x = 5

Step-by-step explanation:

Solve for x:

2 x + 3 = 13

Hint: | Isolate terms with x to the left hand side.

Subtract 3 from both sides:

2 x + (3 - 3) = 13 - 3

Hint: | Look for the difference of two identical terms.

3 - 3 = 0:

2 x = 13 - 3

Hint: | Evaluate 13 - 3.

13 - 3 = 10:

2 x = 10

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 2 x = 10 by 2:

(2 x)/2 = 10/2

Hint: | Any nonzero number divided by itself is one.

2/2 = 1:

x = 10/2

Hint: | Reduce 10/2 to lowest terms. Start by finding the GCD of 10 and 2.

The gcd of 10 and 2 is 2, so 10/2 = (2×5)/(2×1) = 2/2×5 = 5:

Answer:  x = 5

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3 years ago
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A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w
DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{X - 21.5}{4.7}

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X = 27.0225

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

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Answer:

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