The GCF is of 11ab +32ab is 43ab
sin(4π21). Explanation: Notice that this fits the form of the sine subtraction formula: sin(A−B)=sin(A)cos(B)−cos(A)sin(B).
Answer:
<h3>#5</h3>
<u>Given vertices:</u>
These have same x-coordinate, so when connected form a vertical segment.
<u>The length of the segment is:</u>
The area of the rectangle is 72 square units, so the horizontal segment has the length of:
<u>Possible location of the remaining vertices (to the left from the given):</u>
and
<h3>#6</h3>
<u>Similarly to previous exercise:</u>
- (5, -8) and (5, 4) given with the area of 48 square units
<u>The distance between the given vertices:</u>
<u>The other side length is:</u>
<u>Possible location of the other vertices (to the right from the given):</u>
and
Total impedance of circuit is Z1 + Z2
Here it is important that real numbers we sum with real numbers and complex numbers with complex numbers
Let Zs represent total impedance.
Zs = Z1 + Z2 = 3 + 4i + 5 - 2i = 3 + 5 + 4i - 2i = 8 + 2i
Answer is :
8+2i
plsss go ahead and tell your problem
