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Masteriza [31]
3 years ago
8

Simplify (7x)*exponent 2*

Mathematics
2 answers:
leva [86]3 years ago
7 0
(7x)^2 simplified is 49x^2 or 49 and x raised to the second power, since 7•7 is 49, and we dont know the value of x, your answer is 49x^2
Stels [109]3 years ago
5 0

Answer:

49 x^2

Step-by-step explanation:

Simplify the following:

(7 x)^2

Hint: | Distribute exponents over products in (7 x)^2.

Multiply each exponent in 7 x by 2:

7^2 x^2

Hint: | Evaluate 7^2.

7^2 = 49:

Answer:  49 x^2

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hammer [34]
It would be c 15/22 as the answer
8 0
2 years ago
- Which is greater?<br> 5 2<br> a) or<br> 16 9
azamat

Answer:

5/2

Step-by-step explanation:

5/2= 2 1/2

while 16/9=1 7/9

6 0
3 years ago
How do you simplify this?<br>x²y+xy² / y²+2/5 × xy​​​
polet [3.4K]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

Factor out 1/5.

\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

_____

Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

This can further simplified to as \downarrow

=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

3 0
3 years ago
How do you do: -6(6a-5)=-2(8-5a)
devlian [24]

Answer:

a = 1

Step-by-step explanation:

1. distribute the -6 on the left into the parentheses. you should get -36a + 30.

2. on the side right of the =, distribute the -2 to get -16 + 10a.

now it should look like -36a + 30 = -16 + 10a.

3. move the terms over to isolate the a value. subtract 30 to the right side to get -46 (-36a=-46+10a)

4. move the 10a on the right to the left by subtracting it to the other side.

(-46a=-46)

5.divide by -46 to get a=1

7 0
3 years ago
Which answer includes the intrevals that contain the solution to the inequality x^2-1/3x+9&lt;0
victus00 [196]

Answer:

x<±1 and x< -3

Step-by-step explanation:

Given the inequality x^2-1/3x+9<0, we are to find the values of x that satisfies the inequality

x^2-1/3x+9<0

x^2-1/3x+9 (3x+9)²<0*  (3x+9)²

(x^2-1)(3x+9) < 0

x²-1 < 0 and 3x + 9 <0

x²-1 < 0

x²<1

x<±√1

x<±1

Also 3x + 9 <0

3x < -9

x < -9/3

x < -3

Hence the required values of x are x<±1 and x< -3

4 0
3 years ago
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