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Nitella [24]
3 years ago
13

What is the domain of f(x)=^3 sqrt x?

Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0
ANSWER

Domain is all real numbers.

EXPLANATION

We want to find the domain of the function,

f(x) = \sqrt[3]{x}

The domain of this function refers to all values of x that will make the function defined.

When we plug in all real values into the above function, there will be a corresponding functional value.

Therefore the domain is all real numbers.

Or

x \in \: R

Or

( - \infty ,+ \infty)
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Trigonometry<br> Trigonometric Functions<br> Given: Sin θ = (2/3), Find: Cos θ
Mumz [18]
I created this step by step to help, hope it helps ! :)
5 0
3 years ago
Can somebody please help me answer this
ICE Princess25 [194]
Hello!

You solve this algebraically.

2(x - 3) + 4 = 2x + 3x - 5

Distribute the 2

2x - 6 + 4 = 2x + 3x - 5

Combine like terms

2x - 2 = 5x - 5

Subtract 2x from both sides

-2 = 3x - 5

Add 5 to both sides

3 = 3x

Divide both sides by 3

x = 1

The answer is D)1

Hope this helps!
6 0
3 years ago
Read 2 more answers
JNZ~ KOA. Find the unknown measures
shepuryov [24]

Answer:

<h2>x = 8.5in, y = 17in, r = 28°, s = 62°</h2>

Step-by-step explanation:

If ΔJNZ and ΔKOA are similar, then corresponding sides are in proportion and corresponding angles are congruent.

We have the proportion:

\dfrac{JN}{KO}=\dfrac{NZ}{OA}=\dfrac{ZJ}{AK}

and equations:

m\angle N=m\angle O=90^o\\m\angle Z=m\angle A=28^o\\m\angle J=m\angle K=62^o

We have:

JN=8\ in,\ NZ=15\ in,\ KO=4\ in,\ AK=x\ in,\ ZJ=y\ in

For y we must use the Pythagorean theorem:

ZJ^2=JN^2+NZ^2\\\\y^2=8^2+15^2\\\\y^2=64+225\\\\y^2=289\to y=\sqrt{289}\\\\y=17\ in

\dfrac{JN}{KO}=\dfrac{ZJ}{AK}\to\dfrac{8}{4}=\dfrac{17}{x}        <em>cross multiply</em>

8x=(4)(17)

8x=68          <em>divide both sides by 8</em>

x=8.5\ in

4 0
3 years ago
Read 2 more answers
- 8y + 9x = -5<br> 8y + 7x = -75
IRINA_888 [86]

Answer:

x = -5 , y = -5

Step-by-step explanation:

- 8y + 9x = -5

8y + 7x = -75

__________

0 + 16x = - 80

x = -80 / 16

x = -5

- 8y + 9x = -5

-8y + 9(-5) = -5

-8y - 45 = -5

-8y = -5 + 45

-8y = 40

y = 40/-8

y = -5

hope it helps!

8 0
3 years ago
C(n)=−6+5(n−1) find the 8th term in the sequence
AleksAgata [21]

Answer:

Step-by-step explanation:

n = 8

c(n) = -6+5(n - 1)

c(8) = -6+5(8 - 1)

c(8) = -6+5( 7)

c(8) = -6+5(7)

c(8) = -6+35

c(8) =  29

============

Here is the series.

-6

-1

4

9

14

19

24

29

4 0
3 years ago
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