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victus00 [196]
4 years ago
11

Take my points........

Mathematics
2 answers:
Nina [5.8K]4 years ago
8 0
Any questions ???????
Mumz [18]4 years ago
8 0

Answer:

You got a question?

Step-by-step explanation:

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What is the answer need it
denis-greek [22]

Answer:

\frac{7}{10} |

Step-by-step explanation:

STEP 1:

2/3 + 7/10 = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(2/3, 7/10) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(\frac{2}{3} * \frac{10}{10}) + (\frac{7}{10} * \frac{3}{3}) = ?

Complete the multiplication and the equation becomes

\frac{20}{30} + \frac{21}{30}

The two fractions now have like denominators so you can add the numerators.

Then:

\frac{20+21}{30} = \frac{41}{30}

This fraction cannot be reduced.

The fraction 41/30

is the same as

41 divided by 30

Convert to a mixed number using

long division for 41 ÷ 30 = 1R11, so

41/30 = 1 11/30

Therefore:

2/3+7/10= 1 11/30

STEP 2:

41/30 + -2/3

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(41/30, -2/3) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(\frac{41}{30} *\frac{1}{1} ) + ( \frac{-2}{3} * \frac{10}{10} )

The two fractions now have like denominators so you can add the numerators.

Then:

\frac{41+-20}{30} = \frac{21}{30}

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using

GCF(21,30) = 3

\frac{21/3}{30/3} =\frac{7}{10}

Therefore:

\frac{41}{30} + \frac{-2}{3} =\frac{7}{10}|

8 0
3 years ago
The water level at a pier is modeled by the function y= 2.5 cos(2pi/12.5) +12, where y represents the water level measured in me
ivolga24 [154]

Answer: 3.1 hours

Step-by-step explanation: Just took the quiz on edg.

3 0
4 years ago
A 12,000-lb killer whale might eat as much as 14,000 lb of fish per month (assume a 30-day month). If the average weight of a ce
brilliants [131]

Answer:

2196 fish

Step-by-step explanation:

Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb

Weight of the fish that killer whale might eat in a day = \frac{14000}{30} = \frac{1400}{3} lb.

Average weight of the fish that killer whale eats = 3.4 oz

Since,

1 pound(lb) = 16 ounces(oz)

So,

Weight of the fish that killer whale might eat in a day in ounces(oz) = \frac{1400}{3} \times 16=\frac{22400}{3} oz

Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.

So, the number of fish that killer whale would eat = \frac{22400}{3} \div 3.4 = 2196 fish

Thus, the killer whale needs to eat 2196 fish.

8 0
4 years ago
Reflection coordinate plane
Kruka [31]
(-2,-3)

Mirror the point across the x-axis. If it is at (-2,3) then the reflection would be (-2, -3)
5 0
3 years ago
When maras math project was graded, her teacher gave her 40 points
Law Incorporation [45]

Answer:

The answer is D

5 0
3 years ago
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