Answer:
No I do not agree with Andre says that 3 divided by 2/3 Solving for 3 ÷ 2/3
3 ÷ 2/3
= 3 × 3/2
= 9/2
= 4 1/2
Therefore, 3 divided by 2/3 is 4 1/2
Andre's reasoning is wrong.
Step-by-step explanation:
It is incorrect
Let's divide and compare the sum
3 : 2/3 = 3*3/2 = 9/2 = 4 1/2
and
There are four 2/3 fractions and one 1/3 fraction
The 1/3 fraction is 1/2 of 2/3 fraction so instead of counting 1/3 as 1/3 it should be counted as 1/2
Answer:
110%
Step-by-step explanation:
3,927/3,570
=1.1
=110%
Answer:
x=8.75
Step-by-step explanation:
The price x that maximizes profit is the maximum value of the function, and the maximum value of the function is located at a point where the first derivative of the function is equal to zero. The first derivative is:
![P(x) = - 2x^2+35x-99\\P'(x)=-2(2)x^{(2-1)}+35(1)-0\\P'(x)=-4x+35](https://tex.z-dn.net/?f=P%28x%29%20%3D%20-%202x%5E2%2B35x-99%5C%5CP%27%28x%29%3D-2%282%29x%5E%7B%282-1%29%7D%2B35%281%29-0%5C%5CP%27%28x%29%3D-4x%2B35)
Using P'(x)=0:
![0=-4x+35\\4x=35\\x=35/4\\x=8.75](https://tex.z-dn.net/?f=0%3D-4x%2B35%5C%5C4x%3D35%5C%5Cx%3D35%2F4%5C%5Cx%3D8.75)
The minimum value of the function is also at a point where the first derivative of the function is equal to zero. To differentiate if x=8. is a minimum or a maximum obtain the second derivative and evaluate it at x=8.75 if the value P''(x)>0 x is minimum and if P''(x)<0 x is a maximum.
![P'(x)=-4x+35\\P''(x)=-4(1)\\P''(x)=-4](https://tex.z-dn.net/?f=P%27%28x%29%3D-4x%2B35%5C%5CP%27%27%28x%29%3D-4%281%29%5C%5CP%27%27%28x%29%3D-4)
Evaluating at x=8.75:
![P''(8.75)=-4](https://tex.z-dn.net/?f=P%27%27%288.75%29%3D-4)
Therefore, x=8.75 is the maximum value of the function and it is the price that maximizes profit.
You can use the Ruffini's rule. The answer using this method is,
![(x-3) (x+4)^2 (6 + x^2)](https://tex.z-dn.net/?f=%28x-3%29%20%28x%2B4%29%5E2%20%286%20%2B%20x%5E2%29)
And you can see that the multiplicity of the zero x=-4 is 2, and the multiplicity of the zero x=+3 is 1.