<span><span>4<span>(<span>x−b</span>)</span></span>=x</span>Step 1: Add -x to both sides.<span><span><span><span>−<span>4b</span></span>+<span>4x</span></span>+<span>−x</span></span>=<span>x+<span>−x</span></span></span><span><span><span>−<span>4b</span></span>+<span>3x</span></span>=0</span>Step 2: Add 4b to both sides.<span><span><span><span>−<span>4b</span></span>+<span>3x</span></span>+<span>4b</span></span>=<span>0+<span>4b</span></span></span><span><span>3x</span>=<span>4b</span></span>Step 3: Divide both sides by 3.<span><span><span>3x/</span>3</span>=<span><span>4b/</span>3</span></span><span>x=<span><span>4/3</span>b</span></span>Answer:<span>x=<span><span>4/3</span><span>b</span></span></span>
2x+2=2x+5
-2=2x+2
2x=2x+7
_____
2 = 2 +7
x=1+7
no solution
Sample Response: The object will hit the ground after 5 seconds. You can rewrite the quadratic function as a quadratic equation set equal to zero to find the zeros of the function 0 = –16t2 + 80t + 0. You can factor or use the quadratic formula to get t = 0 and t = 5. Therefore, it is on the ground at t = 0 (time of launch) and then hits the ground at t = 5 seconds
What did you include in your response? Check all that apply.
I Rewrite the quadratic function as a quadratic equation set equal to zero: 0 = –16t2 + 80t + 0.
Use the quadratic formula to solve for the zeros.
Factor to solve for the zeros.
t = 0 and t = 5 seconds.
The object will hit the ground after 5 seconds.