3 years ago

In the function f(x)=6x^2-4, what is the value of f(-2)?

Mathematics

1 answer:

BartSMP [9]3 years ago

4 0

In order to find the value of f(-2), you can plug -2 wherever x is.

f(x) = 6x^2 - 4

f(-2) = 6(-2)^2 - 4

f(-2) = 6(4) - 4

f(-2) = 24 - 4

f(-2) = 20

Thus, the value of f(-2) is 20. Hope this helps! If you have any other questions related to this, let me know.

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