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densk [106]
3 years ago
9

Identify the slope and intercept of the following linear equation y=3/4x-2

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
5 0

y= \frac 3 4 x-2

That's in slope-intercept form, y = mx + b, so the slope, the m, is the coefficient on x, namely

\dfrac 3 4

and the y intercept is the constant term, here

-2

Anon25 [30]3 years ago
3 0

y =  \frac{3}{4} x - 2 \\ 2 =  \frac{3}{4}x  - y \\ 1 =  \frac{3}{4 \times 2} x -  \frac{y}{2}  \\  \frac{x}{ \frac{8}{3} }  -  \frac{y}{2}  = 1

So x intercept is 8/3

Hope it helps...

Regards;

Leukonov/Olegion.

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MAVERICK [17]

Answer:

Step-by-step explanation:

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2 years ago
Find the absolute extrema of the function over the region R. (In each case, R contains the boundaries.) Use a computer algebra s
algol [13]

<em>f(x, y)</em> = <em>x</em> ² - 4<em>xy</em> + 5

has critical points where both partial derivatives vanish:

∂<em>f</em>/∂<em>x</em> = 2<em>x</em> - 4<em>y</em> = 0   ==>   <em>x</em> = 2<em>y</em>

∂<em>f</em>/∂<em>y</em> = -4<em>x</em> = 0   ==>   <em>x</em> = 0   ==>   <em>y</em> = 0

The origin does not lie in the region <em>R</em>, so we can ignore this point.

Now check the boundaries:

• <em>x</em> = 1   ==>   <em>f</em> (1, <em>y</em>) = 6 - 4<em>y</em>

Then

max{<em>f</em> (1, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = 6 when <em>y</em> = 0

max{<em>f</em> (1, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = -2 when <em>y</em> = 2

• <em>x</em> = 4   ==>   <em>f</em> (4, <em>y</em>) = 12 - 16<em>y</em>

Then

max{<em>f</em> (4, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = 12 when <em>y</em> = 0

max{<em>f</em> (4, <em>y</em>) | 0 ≤ <em>y</em> ≤ 2} = -4 when <em>y</em> = 2

• <em>y</em> = 0   ==>   <em>f</em> (<em>x</em>, 0) = <em>x</em> ² + 5

Then

max{<em>f</em> (<em>x</em>, 0) | 1 ≤ <em>x</em> ≤ 4} = 21 when <em>x</em> = 4

min{<em>f</em> (<em>x</em>, 0) | 1 ≤ <em>x</em> ≤ 4} = 6 when <em>x</em> = 1

• <em>y</em> = 2   ==>   <em>f</em> (<em>x</em>, 2) = <em>x</em> ² - 8<em>x</em> + 5 = (<em>x</em> - 4)² - 11

Then

max{<em>f</em> (<em>x</em>, 2) | 1 ≤ <em>x</em> ≤ 4} = -2 when <em>x</em> = 1

min{<em>f</em> (<em>x</em>, 2) | 1 ≤ <em>x</em> ≤ 4} = -11 when <em>x</em> = 4

So to summarize, we found

max{<em>f(x, y)</em> | 1 ≤ <em>x</em> ≤ 4, 0 ≤ <em>y</em> ≤ 2} = 21 at (<em>x</em>, <em>y</em>) = (4, 0)

min{<em>f(x, y)</em> | 1 ≤ <em>x</em> ≤ 4, 0 ≤ <em>y</em> ≤ 2} = -11 at (<em>x</em>, <em>y</em>) = (4, 2)

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8 0
3 years ago
the area of a rectangular window is 6216 cm^2. if the length of the window is 84 cm, what is it's width?​
Rus_ich [418]

Answer:

<h3>The answer is 74 cm</h3>

Step-by-step explanation:

The area of a rectangle = length × width

Since we are finding the width

We have

width  = \frac{area}{length}  \\

From the question

area = 6216 cm²

length = 84 cm

The width is

width =  \frac{6216}{84}  \\

We have the final answer as

<h3>74 cm</h3>

Hope this helps you

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Alexeev081 [22]
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The decimal parts are 0.63 and 0.36.
Sixty-three hundredths is greater than thirty-six hundredths.
Since 0.63 is greater than 0.36, 36.63 is greater.
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