Question

A train covers certain distance in two parts. Distance covered in first part is 200% more than the distance covered in second part while speed of train is in the ratio 2 : 1 in first and second part respectively. If average speed of train is 64 km/hr, then find the speed of train in first part? (in kmph)

Answer 1

Answer:

Part A speed=96*2=192km/h

Step-by-step explanation:

Two parts, parts A and part B

Part A=200% more than B

Let part B=x

Part A=200 more than B

=2x

Speed ratio=2:1

Average speed of train=64km/h

Let Part A speed=2x

Part B speed=x

A:B=2:1

Total ratio =3

Speed in the part A can be calculated thus:

Totatl speed= ratio of speed in part A / total ratio

64=2x/3

192=2x

x=96km/h

Part A speed=96*2=192km/h