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4 years ago

5

the ratio of lynx to mountain lions and wolverines in the park is 2:3:1. So far every 2 lynx there are 3 mountain lions and 1 wo

lverine

1 answer:

marusya05 [52]4 years ago

5 0

Hat sounds right to me

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Midtown barber shop conducts 112 haircuts per day. assume each barber works 8 hours per day and take the same amount of time to

goblinko [34]

Since each barber works 8 hours per day, it means that the barber shop conducts 112 haircuts in 8 hours. This means that it conducts

$\cfrac{112}{8} = 14$

cuts per hour. Every barber can conduct two haircuts per hour. This means that a generic number $b$ of barbers conducts $2b$ cuts per hour. But we already know that the shop conducts 14 cuts per hour, so the number of barbers is given by

$2b = 14 \iff b = \cfrac{14}{2} = 7$

8 0

4 years ago

Marking brainliest .

nikdorinn [45]

I’m pretty sure that is B because friday is 4 times more than monday.

8 0

3 years ago

Rikki's hourly salary is $9.64. Last week she worked a 22-hour week. How much did she earn?

jek_recluse [69]

<h3>Answer: 212.08 dollars</h3>

Work Shown: Multiply 9.64 and 22 to get 9.64*22 = 212.08

7 0

4 years ago

What is the nth term rule of the quadratic sequence below?

Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

<u>Given sequence</u>:

6, 20, 40, 66, 98, 136, ...

Calculate the <u>first differences</u> between the terms:

$6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136$

As the first differences are not the same, calculate the <u>second differences:</u>

$14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38$

As the <u>second differences are the same</u>, the sequence is quadratic and will contain an n² term.

The <u>coefficient</u> of the n² term is <u>half of the second difference</u>.

Therefore, the n² term is: 3n²

Compare 3n² with the given sequence:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

The second operations are different, therefore calculate the differences <em>between</em> the second operations:

$3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18$

As the differences are the same, we need to add 5n as the second operation:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2 &-2 & -2 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0

2 years ago

How do you solve interquartile range?

77julia77 [94]

By Hand
Step 1:
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 2:
Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 3:
Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).

Step 4:
Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.

Step 5:
Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.

5 0

3 years ago

Read 2 more answers