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ra1l [238]
4 years ago
5

the ratio of lynx to mountain lions and wolverines in the park is 2:3:1. So far every 2 lynx there are 3 mountain lions and 1 wo

lverine
Mathematics
1 answer:
marusya05 [52]4 years ago
5 0
Hat sounds right to me
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Determine the unit of measurement that best represents each scenario.
BARSIC [14]

Answer:

pounds, ounces, tons

Step-by-step explanation:

7 0
2 years ago
6.4f 24 water bottles weigh 30 pounds, how much would a shipment of 150 water bottles weigh?​
Marizza181 [45]

Answer:

120 pounds

Step-by-step explanation:

24÷30 =0.8

0.8 x 150= 120 pounds

7 0
2 years ago
Larry, Barry, Terry are saving their money for a trampoline that costs $340.
Flauer [41]

Answer:

Larry=X

Barry=112x

Terry=113x

L+B+T=322

x+112x++113x=322

226×=322

Larry saved $1.42

7 0
3 years ago
Can anyone PLEASE help geometry is my worst subject!
seropon [69]
You would have to bring it closer to the stage. At that point initially in the diagram, the angle is 25°. As you can see, the angle is small. But when you bring it closer to the stage, the opening would also increase. Otherwise, if you move it farther away, the opening becomes even smaller.
8 0
3 years ago
What is the probability that a randomly selected member of a normally distributed population will lie more than 1.8 standard dev
Helen [10]

Answer:

P(X> \mu +1.8\sigma)=P(\frac{X-\mu}{\sigma}>\frac{\mu +1.8\sigma-\mu}{\sigma})=P(Z>1.8)

And we can find this probability using the complement rule:

P(z>1.8)=1-P(z

And using the normal standard distirbution table or excel we got:

P(z>1.8)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable if interest of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

We are interested on this probability

P(X>\mu +1.8 \sigma)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X> \mu +1.8\sigma)=P(\frac{X-\mu}{\sigma}>\frac{\mu +1.8\sigma-\mu}{\sigma})=P(Z>1.8)

And we can find this probability using the complement rule:

P(z>1.8)=1-P(z

And using the normal standard distirbution table or excel we got:

P(z>1.8)=1-P(z

5 0
4 years ago
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