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Marat540 [252]
3 years ago
14

Please help I will mark brainliest!!! (10 points)

Mathematics
2 answers:
Artist 52 [7]3 years ago
8 0

Answer:

a. h = 700

b. j = 6400

c. g = 50

Step-by-step explanation:

Translate each statement into an equation and solve the equation. Remember that to change a percent to a decimal, you divide the percent by 100, which is the same as moving the decimal point two places to the left. Also, a percent of a number means a percent times the number.

a. 20% of h is 140

20% * h = 140

0.2h = 140

Divide both sides by 0.2

h = 700

b. 5% of j is 320

5% * j = 320

0.05j = 320

Divide both sides by 0.05

j = 6400

c. 30% of g is 15

30% * g = 15

0.3g = 15

Divide both sides by 0.3

g = 50

krek1111 [17]3 years ago
7 0

Answer:

A: 700

B: 6400

C: 50

Step-by-step explanation:

A: You can multiply by 5

B: You can just multiply by 20.

C: Every 10% is 5, because 15(30%)/3 is 5. 5 times 10 is 50.

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4 0
4 years ago
Given the function f(x) = 4(2)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
Dmitry [639]

Answer:

Step-by-step explanation:

I'm sure you want your functions to appear as perfectly formed as possible so that others can help you.  f(x) = 4(2)x should be written with the " ^ " sign to denote exponentation:  f(x) = 4(2)^x

                                                                                      f(b) - f(a)

The formula for "average rate of change" is a.r.c. = --------------

                                                                                           b - a

                                    change in function value

This is equivalent to  ---------------------------------------

                                            change in x value

For Section A:  x changes from 1 to 2 and the function changes from 4(2)^1 to  4(2)^2:  8 to 16.  Thus, "change in function value" is 8 for a 1-unit change in x from 1 to 2.  Thus, in this Section, the a.r.c. is:

                 8

               ------ = 8 units    (Section A)

                  1

Section B:  x changes from 3 to 4, a net change of 1 unit:  f(x) changes from

4(2)^3 to 4(2)^4, or 32 to 256, a net change of 224 units.  Thus, the a.r.c. is

        224 units

      ----------------- = 224 units (Section B)

            1 unit

The a.r.c for Section B is 28 times greater than the a.r.c. for Section A.

This change in outcome is so great because the function f(x) is an exponential function; as x increases in unit steps, the function increases much faster (we say "exponentially").

7 0
3 years ago
Find a better estimate of √2.
Goryan [66]
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I used the prime factorization method.
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4 0
2 years ago
Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm
GuDViN [60]
Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones). 

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

P(x \ \textless \  3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \  3) \approx 0.00951836732 }


Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.


5 0
4 years ago
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