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icang [17]
4 years ago
6

15=5x+45 answerhurry

Mathematics
2 answers:
tigry1 [53]4 years ago
7 0
I believe that the correct answer is 6.
natta225 [31]4 years ago
6 0
15=5x+45
-45 -45

-30=5x
/5 /5

-4=x
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Simplify the trigonometric expression tan(2x)/tan(x) using double-angle identities !!
jok3333 [9.3K]

 

\displaystyle\\\text{We use the formula: }~~~\tan(2x)=\frac{2\tan(x)}{1-\tan^2(x)}\\ ---\\\\\frac{\tan(2x)}{\tan(x)}=\frac{\dfrac{2\tan(x)}{1-\tan^2(x)}}{\tan(x)}=\frac{2\tan(x)}{\tan(x)\Big(1-\tan^2(x)\Big)}=\boxed{\frac{2}{1-\tan^2(x)}}\\\\\\ \text{Correct answer:~~A.}

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3 years ago
The measure of the exterior angle of the triangle is what?
nalin [4]

( 8 + 13 )

if you add them all together then divide thats u answer !

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3 years ago
A planter shaped like a rectangular prism has a length of 4 meters, a width of 4 meters, and a height of 3 meters. Attached to t
Blababa [14]

Answer:

Planter 1 is 48 meters cubed

Planter 2 is 24 meters cubed

Total volume = 72

Step-by-step explanation:

The formula for the volume of a rectangular prism is length times width times height. So, 4*4*3. This equals 48. If the other planter is half the volume, divide 48 by 2 to get 24 meters cubed. To find the total area add both results to get a total of 72 meters cubed.

3 0
3 years ago
UCF believes that the average time someone spends in the gym is 56 minutes. The university statistician takes a random sample of
11111nata11111 [884]

Answer:

We conclude that the average time someone spends in the gym is different from 56 minutes.

Step-by-step explanation:

We are given that UCF believes that the average time someone spends in the gym is 56 minutes.

The university statistician takes a random sample of 32 gym goers and finds the average time of the sample was 50 minutes. Assume it is known the standard deviation of time all people spend in the gym is 8 minutes.

<u><em>Let </em></u>\mu<u><em> = population average time someone spends in the gym</em></u>

SO, <u>Null Hypothesis</u>, H_0 : \mu = 56 minutes   {means that the average time someone spends in the gym is 56 minutes}

<u>Alternate Hypothesis</u>, H_A : \mu\neq 56 minutes   {means that the average time someone spends in the gym is different from 56 minutes}

The test statistics that will be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                         T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where,  \bar X = sample average time someone takes in the gym = 50 min

              \sigma = population standard deviation = 8 minutes

              n = sample of gym goers = 32

So, <em><u>test statistics</u></em>  =   \frac{50-56}{\frac{8}{\sqrt{32} } }

                               =  -4.243

<em>Since in the question we are not given the level of significance so we assume it to b 5%. Now at 5% significance level, the z table gives critical value between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lie within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the average time someone spends in the gym is different from 56 minutes.

4 0
3 years ago
Lyn asked some of her classmates how many people are normally at home for dinner. She recorded her results in the histogram show
erma4kov [3.2K]

Step-by-step explanation:

There is no diagram so I cannot understand how to answer

3 0
3 years ago
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