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viva [34]
2 years ago
6

Rewrite the equation below in Graphing Form: 2. y = x2 8x + 31

Mathematics
2 answers:
Alik [6]2 years ago
6 0

Answer:

y=x^28x+31

Step-by-step explanation:

bogdanovich [222]2 years ago
4 0

Answer:   y= x 4 − 6 y = 1 x − 2

Step-by-step explanation:

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After your yearly checkup, the doctor has some bad news and some good news. The bad news is that you tested positive for a serio
Maru [420]

Answer:

0.009804

Step-by-step explanation:

We are given;

probability of testing positive given that you have the disease is 0.99

Also, probability of not testing positive and not having the disease is 0.99

We are also told that it is a rare disease and so strikes only 1 in 1000 people = 0.0001

Let's denote positive test by T+, negative test by T¯, having the disease by D+, not having the disease by D¯.

So, we can now denote all the values in probability we have written earlier.

Thus:

P(T+ | D+) = 0.99

P(T¯ | D¯) = 0.99

P(D+) = 0.0001

Thus, P(D¯) = 1 - P(D+) = 1 - 0.0001 = 0.9999

Now, let's find probability of testing positive;

P(T+) = (P(T+ | D+) × P(D+)) + (P(T+ | D¯) × P(D¯))

Now, (P(T+ | D¯) is not given but by inspection, we can infer from the values given that it is 0.01

Thus;

P(T+) = (0.99 × 0.0001) + (0.01 × 0.9999)

P(T+) = 0.010098

Chances that one has the disease would be gotten from Baye's theorem;

P(D+ | T+) = (P(T+ | D+) × P(D+))/P(T+) = (0.99 × 0.0001)/0.010098 = 0.009804

7 0
3 years ago
Why do planets orbit
Klio2033 [76]

Answer:

Newton realized that the reason the planets orbit the Sun is related to why objects fall to Earth when we drop them. The Sun's gravity pulls on the planets, just as Earth's gravity pulls down anything that is not held up by some other force and keeps you and me on the ground.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
22) Daniel won 55 pieces of gum playing
fenix001 [56]

Answer:

26 friends

Step-by-step explanation:

6 0
3 years ago
Write an equation of a line in slope-intercept form with the given slope and y-intercept:
weeeeeb [17]

Answer:

y=3/4x-8

Step-by-step explanation:

3 0
3 years ago
What is the critical value for a chi-square test with 13 degrees of freedom at the 1 percent level of significance
vagabundo [1.1K]

Answer: 27.688

Step-by-step explanation:

The critical chi-square value \chi^2_{(df,\alpha)} depends on significance level (\alpha)  and degrees of freedom (df) .

Given significance level: (\alpha) = 1% = 0.01

Degrees of freedom (df)= 13

From the chi-square table, the critical chi-square value for df = 13 and \alpha =0.01

is \chi^2_{(df,\alpha)}=27.688

Hence, the  required critical value = 27.688

4 0
3 years ago
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