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viva [34]
3 years ago
6

Rewrite the equation below in Graphing Form: 2. y = x2 8x + 31

Mathematics
2 answers:
Alik [6]3 years ago
6 0

Answer:

y=x^28x+31

Step-by-step explanation:

bogdanovich [222]3 years ago
4 0

Answer:   y= x 4 − 6 y = 1 x − 2

Step-by-step explanation:

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Math Help! I NEED IT ASAP!!!! PLEASE!! WILL UPVOTE,LIKE PAGE,LIKE POSTS AND PICS!!
xenn [34]
Hey there!

6^2 = 36 \\  \\ 36 + 4(3) - 2^4 = 16 \\ \\   \\ \\ 4(3) = 12 \\ \\ \\  36 + 12  - 16 = 32  \\ \\ \\ \\ OR \\ \\ \\ \\ \\ 6^2 + ( 3 + 4) = 48 \\ \\  48  - 2^4 = 32 \\ \\ \\ \\ \\ Your  \\ Answer: 32

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6 0
4 years ago
ABSOLUTELY NO LINKS. please help with percentages
RSB [31]

Answer:

1.307%

4.38%

5.696%

Step-by-step explanation:

7 0
3 years ago
How do I solve this ? (5+i)(4-2i)
denpristay [2]
(5 + i)(4 - 2i)
20 - 10i + 4i - 2i²
20 - 6i - 2(-1)
20 - 6i + 2
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3 0
3 years ago
Given that f(x) = x^2? + 9x + 18 and g(x) = x + 3, find (f ÷ g) (x) and express the result in standard form.​
lawyer [7]

Answer:

x + 6

Step-by-step explanation:

(f ÷ g)(x)

= \frac{x^2+9x+18}{x+3} factorise the numerator

= \frac{(x+3)(x+6)}{x+3} ← cancel the factor (x + 3) on numerator/ denominator

= x + 6

5 0
3 years ago
find two consecutive even integers such that five times the first integer is equal to four times the second integer​
drek231 [11]

Answer:

8 and 10

Step-by-step explanation:

All you need to know to begin setting this up is that to get from one even integer to the next consecutive even integer, add 2.

Start with  x = an even integer (yes, because you say so!)

Next even integer = x + 2

"five times the first integer is equal to four times the second integer"

5x = 4(x + 2)

Distribute the 4.

5x = 4x + 8

Subtract 4x

x = 8

The two integers are 8 and 10

5(8) = 4(10) as desired!

5 0
2 years ago
Read 2 more answers
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