Please help and show all work. 20 points.
1 answer:
The area of the 120° sector is
.. Asector = (1/2)r^2*θ . . . . . . . angle in radians
.. = (1/2)*(24 m)^2*(2π/3)
.. = 192π m^2
The area of the white triangle in that sector is
.. Atriangle = (1/2)r^2*sin(θ)
.. = (1/2)*(24 m)^2*(√3)/2
.. = 144√3 m^2
The area of the shaded segment is the difference of these
.. Asegment = Asector -Atriangle
.. = (192π -144√3) m^2
The 2nd selection is appropriate.
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