Please help and show all work. 20 points.
1 answer:
The area of the 120° sector is .. Asector = (1/2)r^2*θ . . . . . . . angle in radians .. = (1/2)*(24 m)^2*(2π/3) .. = 192π m^2 The area of the white triangle in that sector is .. Atriangle = (1/2)r^2*sin(θ) .. = (1/2)*(24 m)^2*(√3)/2 .. = 144√3 m^2 The area of the shaded segment is the difference of these .. Asegment = Asector -Atriangle .. = (192π -144√3) m^2 The 2nd selection is appropriate.
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