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olchik [2.2K]
3 years ago
14

Verify the identity algebraically: Csc(-x)tanx =-secx

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0

Step-by-step explanation:

Recall that

\sin(-x) = -\sin x

Therefore,

\csc(-x) = \dfrac{1}{\sin(-x)} = -\dfrac{1}{\sin x}

so

\csc(-x)\tan x = \left(-\dfrac{1}{\sin x}\right)\left(\dfrac{\sin x}{\cos x}\right)

\:\:\:\:\:\:\:\:\:= -\dfrac{1}{\cos x} = -\sec x

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Answer:

final answer is 6

Step-by-step explanation:

Given f(x)=6x-2

To find the difference quotient use formula

\frac{f(x+h)-f(x)}{h}

f(x)=6x-2

f(x+h)=6(x+h)-2=6x+6h-2

Now plug it in the formula

\frac{f(x+h)-f(x)}{h}

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Step-by-step explanation:

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Step-by-step explanation:

47.50

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