Ask question

Ask question

All categories

3 years ago

12

Which equation represents the relationship between the side length, x, and the perimeter, y? y = one-fourth x y = 4x y = x + 13.

5 y = x – 13.5

1 answer:

elixir [45]3 years ago

4 0

Answer: B.

Y = 4x

Step-by-step explanation:

Given that the side of a shape is x

The perimeter of the shape is y

Perimeter of a rectangle can be expressed as:

P = 2L + 2W

Where L = length and W = width

But if the shape is a square, and the side of the shape is x, then, the perimeter will be

P = 4x

Where perimeter P = Y

Therefore, perimeter Y will be;

Y = 4x

Therefore, the correct answer is B which is:

Y = 4x

You might be interested in

What is an x and y intercept for 14x+y=140

DanielleElmas [232]

140 divided by 14 is 10. So x is 10. And Y is 140. 140 divided by y (1) =140

4 0

3 years ago

What is the area of a rectangle with side lengths of 5/12 foot and 2/3 foot

Minchanka [31]

Answer: 10/36

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

5m - 4n, when m=5 and n = 3.

tiny-mole [99]

Answer:

5m - 4n

5(5) - 4(3) ( As m= 5 and n= 3)

25 - 12

= 13

8 0

2 years ago

Read 2 more answers

Write the decimal in fractional notation: 0.097 A 97/1000 B 97/10,000 C 970 /1000 D 97/10

jeyben [28]

If you would like to write 0.097 in fractional notation, you can do this like this:

0.097 = 97 / 1000

The correct result would be <span>A 97/1000.</span>

3 0

3 years ago

Three consecutive odd integers have a sum of 27. Find the integers.

jek_recluse [69]

$\sf \bf {\boxed {\mathbb {GIVEN:}}}$

Sum of three consecutive odd integers = $27$

$\sf \bf {\boxed {\mathbb {TO\:FIND:}}}$

The values of the three integers.

$\sf \bf {\boxed {\mathbb {SOLUTION:}}}$

$\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}$

$\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}$

Let us assume the three consecutive odd integers to be $x$ , $(x+2)$ and $(x+4)$ .

As per the condition, we have

$Sum \: \: of \: \: the \: \: three \: \: consecutive \: \: odd \: \: integers = 27$

$➺ \: x + (x + 2) + (x + 4) = 27$

$➺ \: x + x + 2 + x + 4 = 27$

Now, collect the like terms.

$➺ \: (x + x + x) + (2 + 4) = 27$

$➺ \: 3x + 6 = 27$

$➺ \: 3x = 27 - 6$

$➺ \: 3x = 21$

$➺ \: x = \frac{21}{3} \\$

$➺ \: x = 7$

Therefore, the three consecutive odd integers whose sum is $27$ are $\boxed{ 7 }$ , $\boxed{ 9 }$ and $\boxed{ 11 }$ respectively.

$\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}$

$⇢ 7 + 9 + 11 = 27$

$⇢ 27 = 27$

⇢ L. H. S. = R. H. S.

$\sf\blue{Hence\:verified.}$

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}$

4 0

3 years ago