Neither all can be substrates
We need to know what the coordinates of 'X' were BEFORE the reflection.
The only information you've given us so far is the reflection line
and the names of the triangle's vertices.
The point (1, -3) is 4 units below the line y=1.
If you flop it across that line, it winds up 4 units above y=1.
Then it's located at
(1, 5) <===
The answer is to be 9.135
306+122=428
Because you add 6 & 2 in the ones place which is 8.
then 2 and 0 which is 2.
finally 1 and 3 which is 4