Answer:
The answer is D
Step-by-step explanation:
D is the point where the two lines intersect and therefore it is the solution of the line
The euro has depreciated and the dollar as appreciated
Answer:
Step-by-step explanation:
50 dollars = ∉34
∉1 = Rs 150
Rs 382800 / 150 Rs per ∉ = 382800/150 ∉
=2552 ∉
50 dollars = ∉34 so 50/34 dollars = ∉
2552 ∉ × 50/34 dollar per ∉ = in the units the ∉ cancel out
∉ × dollar/∉ = dollars
(2552 × 50) / 34 = 3752.94 dollars <------------------
Here is another way of looking at the answer...........
Rs 382800 × 1∉/150 Rs × 50 dollars/34 ∉ = note how the units cancel
= 382800 × (1/150) × (50/34) Rs × ∉/Rs × dollars/∉
= 3,752.94 dollars leaving only dollars in the numerator
Split the second term in 6x^2 + 17x + 5 into two terms
6x^2 + 15x + 2x + 5 = 0
Factor out common terms in the first two terms, then in the last two terms.
3x(2x + 5) + (2x + 5) = 0
Factor out the common term 2x + 5
(2x + 5)(3x + 1) = 0
Solve for x
<u>x = -5/2, -1/3</u>
Answer:
i). x³ + 9x² + yz - 15
ii). -21m³np - 8p⁵q + mnp + 4mn + 100
Step-by-step explanation:
Question (38)
i). Two expressions are -5x² - 4yz + 15 and x³+ 4x²- 3yz
By subtracting expression (1) from expression (2) we can the expression by addition which we can get expression (1).
(x³+ 4x²- 3yz) - (-5x² - 4yz + 15) = x³ + 4x² - 3yz + 5x² + 4yz - 15
= x³ + 9x² + yz - 15
ii). -15m³np + 2p⁵q - 6m³pn + mnp + 4mn - 10qp⁵+ 100
= (-15m³np - 6m³np) + (2p⁵q - 10qp⁵) + mnp + 4mn + 100
= -21m³np - 8p⁵q + mnp + 4mn + 100
