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2 years ago

HELP HELP PLEASE I WILL MARK YOU BRILL

Mathematics

2 answers:

abruzzese [7]2 years ago

8 0

Answer:

I don’t know how to help you with that because I don’t have your math journal. And stander form of what exactly?

Snowcat [4.5K]2 years ago

5 0

I believe you have to find the exponents that lead to 64 and explain them in standard form

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A circular merry-go-round has a radius of 5 feet. Find the distance of a spin of one full rotation. Use 3.14 for pi and round th

Sedbober [7]

Option C

The distance of a spin of one full rotation is 31.4 feet

<em><u>Solution:</u></em>

Given that,

A circular merry-go-round has a radius of 5 feet

Radius = 5 feet

We have to find the distance of spin for one full rotation

Distance covered in 1 full of rotation is equal to circumference of circle

<em><u>The circumference of circle is given as:</u></em>

$C = 2 \pi r$

Where "r" is the radius

$C = 2 \times 3.14 \times 5\\\\C = 6.28 \times 5\\\\C = 31.4$

Thus the distance of a spin of one full rotation is 31.4 feet

6 0

3 years ago

What value of k will result in the quadratic having one rational solution if 4x2+kx+4=0?

PtichkaEL [24]

The value of 'k' in the quadratic Equation $4x^{2}+kx+4=0$ having one rational solution is k is 8.

<h3>What is a Quadratic Equation?</h3>

Quadratic equations are the polynomial equations of degree 2 in one variable of the type $f(x) = ax^{2} + bx + c = 0$ where a, b, c, ∈ R and a ≠ 0.
The standard form of a quadratic equation is $ax^{2} + bx + c = 0$ .

Here, the given equation is $4x^{2}+kx+4=0$

By comparing the given equation with the standard form of the quadratic equation we get,

a = 4

b = k

c = 4

The given quadratic is having one rational solution, which means $b^{2} -4ac=0$

Therefore,

$k^{2} -4 \times 4\times4=0\\k^{2} -64=0\\k^{2} =64\\k=\sqrt{64} \\k=8$

Therefore, the value of k is 8.

Learn more about the quadratic equation is brainly.com/question/8649555

#SPJ4

7 0

1 year ago

F(x)=5x-2 find the slope of f

Inessa [10]

Answer:

Slope = 5

Step-by-step explanation:

Standard slope intercept form: y = mx + b

where m = slope of the function

so m = 5

Hope this helps!

7 0

2 years ago

The image is the question

solniwko [45]

The answer will me d

4 0

2 years ago

Find the smallest possible value of$$\frac{(y-x)^2}{(y-z)(z-x)} \frac{(z-y)^2}{(z-x)(x-y)} \frac{(x-z)^2}{(x-y)(y-z)},$$where $x

Harlamova29_29 [7]

Answer:

$\frac{(y-x)^2}{(x-y)^2} \frac{(x-z)^2}{(z-x)^2}\frac{(z-y)^2}{(y-z)^2} =1$

And on this case the samllest possible value would be 1

Step-by-step explanation:

For this case we have the following expression:

$\frac{(y-x)^2}{(y-z)(z-x)} \frac{(z-y)^2}{(z-x)(x-y)} \frac{(x-z)^2}{(x-y)(y-z)}$

And we can rewrite this expression like this:

$\frac{(y-x)^2}{(x-y)^2} \frac{(x-z)^2}{(z-x)^2}\frac{(z-y)^2}{(y-z)^2}$

For this case is important to remember the following property from algebra:

$(a-b)^2 = a^2 -2ab + b^2$

$(b-a)^2 = b^2 - 2ab + a^2$

On this case we can see that $(a-b)^2 = (b-a)^2$

So then $(y-x)^2 = (x-y)^2 , (x-z)^2= (z-x)^2, (z-y)^2 =(y-z)^2$

So then we can simplify all the expression and we got this:

$\frac{(y-x)^2}{(x-y)^2} \frac{(x-z)^2}{(z-x)^2}\frac{(z-y)^2}{(y-z)^2} =1$

And on this case the samllest possible value would be 1

3 0

3 years ago