Answer:

Option B
Step-by-step explanation:
<u>Sum of vectors in</u> 
Given two vectors
and
. The sum of both vectors is:

The vectors in the figure are


The sum is


Option B
Answer:
3000 bags
Step-by-step explanation:
In this case we must apply the formula of the mean, which would be the sum of the values divided by the amount of data is the mean:
m = (a1 + a2 ... an) / n
In this case we know the mean, we must know the 1987 data, therefore:
Let x be the number of bags sold in 1987, replacing in the previous equation:
2100 = (1800 + 1500 + x) / 3
2100 * 3 = 3300 + x
x = 6300 - 3300
x = 3000
Therefore, for the average to be a total of 2100 bags in those 3 years, the amount of bag sold in 1987 must have been 3000 bags
The scientist would use milligrams, grams, and kilograms.
The best procedure would be to randomly pick 52 fish from the entire pond and weigh each of them as this would be the most unbiased way to achieve the average mass
Answer:

Step-by-step explanation
We have given that equation of line a+4b=0
⇒4b= -a
⇒
slope of line = 
⇒
is negative therefore it lies into 4th quadrant
By, Pythagoras theorem 
by putting value of P= -1 & B=4
the value of
with the given condition 
i.e.
∈ (3π/2, 2π)
now, 