How much of a stick of butter is 1/2 cup?

Water and oil are mixed in the ratio 3:5. Find the density of the mixture if the density of water is 1g/cm ^3 and that of oil is

kompoz [17]

Answer:

Density of mixture is 7.0 g/ $cm^{3}$ .

Step-by-step explanation:

Density of mixture = density of water in the mixture + density of oil in the mixture

Given: water and oil were mixed in a ratio 3:5

density of water is 1.0 g/ $cm^{3}$ and that of oil is 0.8 g/ $cm^{3}$ .

Then,

density of water in the mixture = 3 x 1.0 g/ $cm^{3}$

= 3.0 g/ $cm^{3}$

Density of the volume of water in the mixture is 3.0 g/ $cm^{3}$ .

density of oil in the mixture = 5 x 0.8 g/ $cm^{3}$

= 4.0 g/ $cm^{3}$

Density of oil in the mixture is 3.0 g/ $cm^{3}$ .

So that,

Density of mixture = 3.0 + 4.0

= 7.0

Density of mixture is 7.0 g/ $cm^{3}$ .

8 0

3 years ago

1. A buoy floats 19 yards from the eastern most point of a boat and 15 yards from the western most point of a second boat. The a

Black_prince [1.1K]

The laws of cosines and law of sines can be used given that two sides

and an included angle, or two angles a side are known.

Response:

1. The other angles in the triangle formed by the buoy are approximately;

31.1° and 40.9°

2. Distance of the helicopter from the first island is approximately;

14.5 miles

<h3>How is the Law of Sines and Cosines used?</h3>

Given parameters are;

Distance of the buoy from the easternmost point of a boat = 19 yards

Distance of the buoy from the westernmost point of the other boat = 15 yards

Angle formed from the buoy to the two boats = 108°

Distance between the two boats, d, is given by the law of cosines, as follows;

d² = 19² + 15² - 2 × 19 × 15 × cos(108°) = 586 - 570·cos(108°)

d = √(586 - 570·cos(108°))

By the law of Sines, we have;

$\dfrac{d}{sin(108^{\circ})} = \mathbf{\dfrac{15}{sin(Angle \ formed \ from \ the \ boat \ on \ the \ West, \ \theta_1)}}$

Which gives;

$sin(\theta_1) = \mathbf{ \dfrac{15 \times sin(108^{\circ})}{\sqrt{586 - 570 \cdot cos(108^{\circ})} }}$

The o

$\theta_1 = arcsin \left( \dfrac{15 \times sin(108^{\circ})}{\sqrt{586 - 570 \cdot cos(108^{\circ})} } \right) \approx \mathbf{31.1^{\circ}}$

The other angles formed in the triangle containing the buoy are;

θ₁ ≈ 31.1

θ₂ ≈ 180° - 108° - 31.1° ≈ 40.9°

2. Distance between the two islands = 20 miles

Angle of elevation with one island = 15°

Angle of elevation with the second island = 35°

Required:

The mileage (distance travelled) of the helicopter.

Solution:

Let A represent the island that has an angle of elevation to the helicopter

of 15°, and let B represent the other island.

Angle formed by the helicopter and the two island, θ, is found as follows;

θ = 180° - (15° + 35°) = 130°

By the Law of Sines, we have;

$\dfrac{20}{sin(130^{\circ})} = \mathbf{ \dfrac{Distance \ from \ island \ A }{sin(35^{\circ})}}$

Which gives;

$Distance \ of \ helicopter \ from \ island \ A = \mathbf{ \dfrac{20}{sin(130^{\circ})} \times sin(35^{\circ})}$

$Mileage \ from \ island \ A = \dfrac{20}{sin(130^{\circ})} \times sin(35^{\circ}) \times cos(15^{\circ}) \approx 14.5$

The mileage of the helicopter from the first island is approximately 14.5 miles

Learn more about the Law of Sines and Cosines here:

brainly.com/question/8242520

brainly.com/question/2491835

7 0

2 years ago

The population pyramid of a city in southern Florida, Arizona, or even northern Japan may have a visual appearance of ________ b

konstantin123 [22]

Answer:

A. upside down

Explanation:

Pyramid population, sometimes called afe-gender population is an illustration showing showing various age group distribution. The illustration usually forms the shape of a pyramid, hence its name as the age group increases. It's assumed there are more younger people than older people in a region or country. In this case, the pyramid population is said to be Upside down, because in those regions listed, the number of elderly people is greater than those of the younger people. Population pyramid usually represents the distribution or breakdown of ages and gender of a region at a given point in time.

7 0

4 years ago

Pls help urgent idk how to solve

VLD [36.1K]

Answer:

look at the picture to be more clear.

Hope it helps

7 0

3 years ago

HELP !!!! Evaluate the expression for the given value of the variable 60/m; m = 5

Savatey [412]

Answer: 12

Step-by-step explanation:

5 0

3 years ago