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natali 33 [55]
3 years ago
7

What is the quotient (2x3 − 3x2 − 14x + 15) ÷ (x − 3)?

Mathematics
2 answers:
Troyanec [42]3 years ago
3 0
2x^2 + 3x - 5

Hope this helps!
sdas [7]3 years ago
3 0

Answer:  The correct option is (a) 2x^2+3x-5.

Step-by-step explanation:  We are given to find the quotient in the following division :

Q=\dfrac{2x^3-3x^2-14x+15}{x-3}.

To find the quotient, first we will try to factorize the numerator and then we will try to divide by the denominator.

We have

Q\\\\\\=\dfrac{2x^3-3x^2-14x+15}{x-3}\\\\\\=\dfrac{2x(x-3)+3x(x-3)-5(x-3)}{x-3}\\\\\\=\dfrac{(x-3)(2x^2+3x-5)}{(x-3)}\\\\=2x^2+3x-5.

Thus, the required coefficient is 2x^2+3x-5.

Option (a) is CORRECT.

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HELP ASAP Use the data below
beks73 [17]

Answer:

Part A:

   -Minimum: 10

   -Q1: 17.5

   -Median: 30

   -Q3: 42.5

   -Maximum: 50

Step-by-step explanation:

Part B: IQR= 25

This shows that the data varies for 25 different numbers. That HALF of the data is between 25 numbers.

Part C: Using a box-and-whisker plot you can interpret the different values. Minimum is the first dot (10), connected to the first line (Q1 which is 17.5), connected by a box to the median (30), connected by a box to the third line (Q3 which is 42.5), connected to the last dot which is the maximum (50). And IQR is Q3-Q1, so 42.5-17.5 which is 25.

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What is the range of this absolute value function? a. -[infinity] < y ≤ 0 b. 0 ≤ y < [infinity] c. -[infinity] < y ≤ 7
tigry1 [53]

If the equation of the absolute value function is f(x) = |x + 1| + 7, then the range of the function is -∞ < y ≤ 7

<h3>How to determine the range of the absolute value function?</h3>

<em>The question is incomplete, so I will provide a general explanation</em>

Assume that the absolute value function is given as:

f(x) = |x + 1| + 7

Set the absolute value to 0

f(x) ≥ 0 + 7

Evaluate

f(x) ≥ 7

This means that the smallest value of the function is 7

Hence, the range of the absolute value function is -∞ < y ≤ 7

Read more about range at:

brainly.com/question/10197594

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