Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
Step-by-step explanation:
There are an infinite number of possible solutions.
here's a few
(1 - 4i) + (-12 + 4i)
(-5.5 + 2i) + (-5.5 + i)
(-24 - 27i) + (13 + 30i)
To the nearest thousand is 23,000 and the nearest ten thousand is 20,000
Answer:
Only 97 is the one that's prime. The answer to the riddle is 97, so check if 79 is "ones digit is two less than my tens digit".
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