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2 years ago

Need help asap!! (summer packet)

Mathematics

1 answer:

DiKsa [7]2 years ago

6 0

Part A:

Function A:

Slope = (7-3)/(5-3) = 4/2 = 2

Equation:

y - 3 = 2(x - 3)

y - 3 = 2x - 6

y = 2x - 3

Funcion B:

(0, 3 ) and (-5, 0)

Slope = (3 - 0)/(0 + 5) = 3/5

y-intercept (0,3) so b = 3

Equation:

y = 3/5 x + 3

Function C:

y = 3x + 1

Part B:

Rate of change is the change in y over the change in x (rise/run). It's also the slope

Function A: rate of change = 2

Function B: rate of change = 3/5 (smallest)

Function C: rate of change = 3 (largest)

Order linear functions based on rate of change from least to greatest.

Function B: y = 3/5 x + 3

Function A: y = 2x - 3

Function C: y = 3x + 1

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$P(17.24\leq X\leq 42.13)=\int\limits^{42.13}_{17.24}{\frac{1}{38.3} e^{-x/38.3}}}\, dx$

$=\frac{1}{38.3}\times \int\limits^{42.13}_{17.24}{ e^{-x/38.3}}}\, dx$

$=\frac{1}{38.3}\times| \frac{e^{-x/38.3}}{-1/38.3}}|^{42.13}_{17.24}\\$

$=-e^{42.13/38.3}+e^{17.34/38.3}\\=-0.3329+0.6375\\=0.3046$

Thus, the probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work is 0.3046.

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