Question

P(-2,4), m=3

Answer 1

$\bf P(\stackrel{x_1}{-2}~,~\stackrel{y_1}{4})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=3[x-(-2)]\implies y-4=3(x+2) \\\\\\ y-4=3x+6\implies y=3x+10$