A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.
There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.
The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.
However, if the question were to say "and," we would multiply the two probabilities.
Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).
Now we can add them together.
This cannot be simplified further, so the probability is 17 in 52, or 33%.
hope this helps!
Total students = 15+21=36, so the probability of choosing a girl is 21/36, which reduces to 7/12.
Total freshmen = 12+15=27, so the probability of choosing a freshman is 27/36, which reduces to 3/4.
Answer:
Option (1)
Step-by-step explanation:
Two functions 'f' and 'g' have been graphed in the picture attached.
Both the functions will be equal at the points where the values of these functions are equal.
Those points are the point of intersection of both the functions on the given graph.
At x = -4,
f(-4) = g(-4) = 4
At x = 0,
f(0) = g(0) = 4
Therefore, Option (1) will be the answer.
<h3>
Answer: 4/25</h3>
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Explanation:
Add up the first two frequencies to get 14+18 = 32
The table shows that the person rolled either a "1" or a "2" a total of 32 times, which is the amount of rolls getting less than "3".
This is out of the 200 rolls total.
32/200 = (8*4)/(8*25) = 4/25
In decimal form, this would be 4/25 = 0.16 which is exact.
