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Anna [14]
1 year ago
13

If a single card is drawn from a standard 52-card deck, what is the probability that it is an ace or a spade?

Mathematics
2 answers:
klasskru [66]1 year ago
7 0

A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.

There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.

The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.

However, if the question were to say "and," we would multiply the two probabilities.

Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).

\frac{1}{4} -- > \frac{13}{52}

\frac{1}{13} -- > \frac{4}{52}

Now we can add them together.

\frac{13}{52} + \frac{4}{52} = \frac{13+4}{52} = \frac{17}{52}

This cannot be simplified further, so the probability is 17 in 52, or 33%.

hope this helps!

Likurg_2 [28]1 year ago
5 0

Answer:

Step-by-step explanation:

4/13

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There are premium tickets costing $99 each and rest are regualr tickets costing $25 each. A pile of 120 tickets have a total val
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There are 38 premium tickets and 82 regular tickets in a pile.

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Total number of tickets = 120

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Let the number of premium tickets be x.

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Total number of tickets is the sum of total number of premium tickets and  total number of regular tickets.

So the equation can be written as;

x+y=120\ \ \ \ \ equation\ 1

Again,total amount  is the sum of total number of premium tickets multiplied by cost of each premium ticket and  total number of regular tickets multiplied by cost of each regular ticket.

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Now We will multiply equation 1 by 25 we get;

x+y=120\\25(x+y)=120\times25\\25x+25y= 3000 \ \ \ \ equation\ 3

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x+y=120\\38+y=120\\y=120-38\\y=82

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