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Rzqust [24]
3 years ago
8

A bicycle pedal is pushed by a foot with a 60-N force which made 75 degrees with the shaft of the pedal. The pedal hand is 12 cm

long. Find the magnitude of the torque about the center of the pedal
Mathematics
1 answer:
laiz [17]3 years ago
6 0

Answer: 6.95Nm

Step-by-step explanation:

A torque of a circular rotating body is calculated by multiplying the force acting on the centre with it's lever arm. If this force acts at an angle like the one we have in the question, we derive our resultant force and use it in our calculations.

F = 60N

Angle = 75°

Sin 75 = 0.9659

Lever arm = 12cm = 0.12m.

Deriving the resultant torque from the given angle becomes:

T = 60 * 0.12 * sin75 = 6.95Nm.

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Answer:

Step-by-step explanation:

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so

adding them together is  21 + (-15) = 6

and then subtracting  21 - (-15) =

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marysya [2.9K]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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