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k0ka [10]
3 years ago
5

Paula ran a total of 12 miles over the course of 2 track practices. What is the unit rate?

Mathematics
2 answers:
Reptile [31]3 years ago
6 0
The unit rate is 6 miles over the course of one track practice. To get this answer, you simply put the numbers 12 and 2 in fraction form, 12/2. Then simplify.
liq [111]3 years ago
5 0

Answer:

\frac{6}{1}

Step-by-step explanation:

To find the unit rate we need to divide the # of miles over the number of practices to get the # of miles ran in a single practice:

\frac{12}{2}=\frac{6}{1}

Hope this helps!

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MrMuchimi

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3. Round 9995.2 to the nearest ten. Explain in your
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Please help me answer this question
avanturin [10]

By <em>direct</em> substitution and simplification, the <em>trigonometric</em> function z = cos (2 · x + 3 · y) represents a solution of the <em>partial differential</em> equation  \frac{\partial^{2} t}{\partial x^{2}} - \frac{\partial^{2} t}{\partial y^{2}} = 5\cdot z.

<h3>How to analyze a differential equation</h3>

<em>Differential</em> equations are expressions that involve derivatives. In this question we must prove that a given expression is a solution of a <em>differential</em> equation, that is, substituting the variables and see if the equivalence is conserved.

If we know that z = \cos (2\cdot x + 3\cdot y) and \frac{\partial^{2} t}{\partial x^{2}} - \frac{\partial^{2} t}{\partial y^{2}} = 5\cdot z, then we conclude that:

\frac{\partial t}{\partial x} = -2\cdot \sin (2\cdot x + 3\cdot y)

\frac{\partial^{2} t}{\partial x^{2}} = - 4 \cdot \cos (2\cdot x + 3\cdot y)

\frac{\partial t}{\partial y} = - 3 \cdot \sin (2\cdot x + 3\cdot y)

\frac{\partial^{2} t}{\partial y^{2}} = - 9 \cdot \cos (2\cdot x + 3\cdot y)

- 4\cdot \cos (2\cdot x + 3\cdot y) + 9\cdot \cos (2\cdot x + 3\cdot y) = 5 \cdot \cos (2\cdot x + 3\cdot y) = 5\cdot z

By <em>direct</em> substitution and simplification, the <em>trigonometric</em> function z = cos (2 · x + 3 · y) represents a solution of the <em>partial differential</em> equation  \frac{\partial^{2} t}{\partial x^{2}} - \frac{\partial^{2} t}{\partial y^{2}} = 5\cdot z.

To learn more on differential equations: brainly.com/question/14620493

#SPJ1

3 0
2 years ago
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