All categories

3 years ago

What is the equation of the line that passes through the point (5, -2) and has a slope of -2/5

Mathematics

1 answer:

Alecsey [184]3 years ago

4 0

Answer:

y=-2/5x

Step-by-step explanation:

y-y1=m(x-x1)

y-(-2)=-2/5(x-5)

y+2=-2/5(x-5)

y=-2/5x+10/5-2

y=-2/5x+2-2

y=-2/5x

You might be interested in

Given f(x) = 4x^2 + 19x - 5 and g(x) = 4x^2 - x what is (f/g)(x)?

Free_Kalibri [48]

$( \frac{f}{g} )(x) = \frac{4 {x}^{2} + 19x - 5}{4 {x}^{2} - x} = \frac{(4x - 1)(x + 5)}{x(4x - 1)} = \frac{x + 5}{x}$

3 0

3 years ago

Read 2 more answers

A company’s sales increased 17% this year, to $8267. What were their sales last year?

Arisa [49]

Answer:

eekk im not shure sorry but it might be 8156 i no no

Step-by-step explanation:

3 0

3 years ago

Otis paints the interior of a home for $45 per hour plus $75 for supplies. Shireen paints the interior of a home for $55 per hou

riadik2000 [5.3K]

Step-by-step explanation:

you should only make one equation:

75 + 45x = 30 + 55x

subtract the 30 frim both sides, then subtract 45x from both sides. you are left with:

45 = 10x

Divide by 10 and get:

4.5 = x

After 4.5 hours, the cost is equal for either worker.

8 0

3 years ago

Read 2 more answers

"let v = r 2 with the usual addition and scalar multiplication defined by k(u1, u2) = (ku1, 0). determine which of the five axio

expeople1 [14]

Let $\mathbf u\in\mathbb R^2$ , where

$\mathbf u=(u_1,u_2)$

and let $k\in\mathbb R$ be any real constant.

Given this definition of scalar multiplication, we can see right away that there is no identity element $e$ such that

$e\mathbf u=\mathbf u$

because

$e\mathbf u=e(u_1,u_2)=(eu_1,0)\neq(u_1,u_2)=\mathbf u$

5 0

3 years ago

Please help! How do I solve this?

Advocard [28]

$m\angle 6=m\angle3\\
8x+7=6x+32\\
2x=25\\
x=12.5\\\\
m\angle 6=8\cdot12.5+7=100+7=107\Rightarrow D
$

5 0

3 years ago