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3 years ago

15

Find the distance between the two points (3, 2 ) and (5, -2)

2 answers:

andreev551 [17]3 years ago

4 0

First of all, you have to imagine a triangle with a line connecting the two points and a verticle and horizontal line. You know that the lengths of the two shorter lines squared and added together will equal the length of the longer line squared because a^2+b^2=C^2, so you need to find the length of the two shorter lines. One line is 2 long (5-3) and the other is 4 long(2--2).2 sqaured is 4 and 4 squared is 16. 16+4 is 20. The answer is square root twenty.

svetoff [14.1K]3 years ago

4 0

It should be, if my math is right,<span>√</span><span>20<span>‾‾‾</span></span>

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insens350 [35]

Answer: a = 8; b = 15; c = 17

Step-by-step explanation:

c = b + 2 and c = 2a + 1

b = c − 2 and a = $\frac{c-1}{2}$

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$c^{2} = (c-2)^{2} + \frac{c-1}{2}\\$

$c^{2}= \frac{4 (c-2)^{2}+(c - 1)^{2} }{4}$

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$c(c -17)-1(c-17)=0$

$(c -1)(c-17)=0$

c = 1 or c = 17

If c = 1 then b = 1 - 2 = -1, that's not possible

So x = 17

b = 17 - 2 = 15

a = $\frac{17-1}{2} = 8$

Length sides of the triangle are 17 cm, 15 cm and 8 cm.

I saw some of this on a site but I want to make sure its correct so we're gonna apply the pythagorean theory and see if its correct.

$a^{2} + b^{2} = c^{2} \\8^{2} + 15^{2} = 17^{2} \\64 + 225 = 289\\289 = 289\\$

This shows that this is correct.

Hope this helped! Again, some of this was from a site, not from me.

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