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Sever21 [200]
3 years ago
15

A couple decided to have 4 children.

Mathematics
1 answer:
AveGali [126]3 years ago
7 0
See below the theee of possibilities:

BBBB
BBBG
BBGB
BBGG
BGBB
BGBG
BGGB
BGGG
GBBB
GBBG
GBGB
GBGG
GGBB
GGBG
GGGB
GGGG

There are 16 differents possibilities.
In 11 of them have at least 2 boys

So probability is 11/16
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<u>Answer-</u>

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r=\frac{n(\sum xy)-\sum x \sum y}{\sqrt{[n\sum x^{2} -({\sum x})^{2}]\times [n\sum y^{2} -({\sum y})^{2}]}}


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