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IceJOKER [234]
3 years ago
13

What does the title Shi huangdi mean

Social Studies
2 answers:
Varvara68 [4.7K]3 years ago
8 0
It means he was the first emperor of china
Ugo [173]3 years ago
8 0
He created a new title for himself: "Huangdi" together with "Shi (means the first)", hence get the name "Qin Shi Huang" or "Qin Shi Huangdi", which means he was the first emperor of China.
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No theocracies are true democracies. no secular government are theocracies. Thus, some secular government are true democracies.
zhenek [66]

Answer:

No theocracies are true democracies. no secular government are theocracies. Thus, some secular government are true democracies.

d. deductive invalid

Explanation:

  • The given statement is deductive as well as invalid.
  • Such a process of logic in which we use the logic of two or more statements to get a final logical conclusion is known as deductive logic.
  • In the given situation, we have concluded that some secular governments are true democracies on the basis of no theocracies are true democracies and no secular government are theocracies.
  • So although, it is deductive logic but it is invalid as well.

3 0
3 years ago
“Father” of Judaism
Stolb23 [73]
The answer to this is A
6 0
3 years ago
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Why did the professional dog walker go out of business math worksheet answers?
Gelneren [198K]
Why Did the Professional Dog Walker ao Out of business, math worksheet Answers:

Q1. sin27°   = x/8

Solution:

We have to solve for x, therefore, we will rearrange the given equation for x.

We get,
x = 8 × sin27°

Using the calculator,

sin27° = 0.45

Now substitute the value of sin27° into the main equation.

we get,
x = 8 × 0.45
x = 3.63 (rounded to the nearest hundredth)


Q2. tan 18°  = n / 75

Solution:
We have to solve for n, therefore, we will rearrange the given equation for n.
We get,
n = 75 × tan 18°
Using the calculator,
tan 18° = 0.32
Now substitute the value of tan 18° into the main equation.
we get,
x = 75 × 0.32
x = 24.37 (rounded to the nearest hundredth)

Q3. sin40°  = 4 / a

Solution: We have to solve for a, therefore, we will rearrange the given equation for a.
We get,
a = 4 ÷ sin40°
Using the calculator,
sin40° = 0.64
Now substitute the value of sin40° into the main equation.
we get,
a = 4 ÷ 0.64
a = 6.25 (rounded to the nearest hundredth)

Q4. cos5°   = 92 / y

Solution: We have to solve for y, therefore, we will rearrange the given equation for y.
We get,
y = 92 ÷ cos5°
Using the calculator,
Cos5° = 0.99
Now substitute the value of cos5° into the main equation.
we get,
y = 92 ÷ 0.99
y = 92.92 (rounded to the nearest hundredth)

Q5:
Given the shape attached, therefore, using the triangle given, we have:
Angle of elevation = 35°
length of Opposite side to the angle = x
Length of Hypoteneus = 12
Calculations:
Using the SOH CAH TOA rules:
SOH stands for SineФ = Opposite ÷ Hypotenuse.

CAH stands for CosineФ = Adjacent ÷ Hypotenuse.

TOA stands for TangentФ = Opposite ÷ Adjacent.

Hence,

               SineФ = Opposite ÷ Hypotenuse

Substituting the values:

               Sine35° = x ÷ 12

               0.5735  = x ÷ 12

                          x = 0.5735 × 12

                          x = 6.88 (rounded to the nearest hundredth)

Q6: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 54°
length of the adjacent side to the angle = x
Length of Hypoteneus = 30
Calculations:
Using the SOH CAH TOA rules:

Hence,

               CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

               Cos54° = x ÷ 30

               0.5877  = x ÷ 30

                          x = 0.5877 × 30

                          x = 17.63 (rounded to the nearest hundredth)

Q7: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 22°
length of the adjacent side to the angle = 85
length of the opposite side to the angle = x
Calculations:

Using the SOH CAH TOA rules:

Hence,

               TangentФ = Opposite ÷ Adjacent

Substituting the values:

               tan22° = x ÷ 85

              0.4040 = x ÷ 85

                          x = 0.4040 × 85

                          x = 34.34 (rounded to the nearest hundredth)

Q8: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 16°
length of the opposite side to the angle = x
Length of Hypoteneus = 14
Calculations:
Using the SOH CAH TOA rules:
Hence,

               CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

               Sine16° = x ÷ 14

               0.2756  = x ÷ 14

                          x = 0.2756 × 14

                          x = 3.86 (rounded to the nearest hundredth)

Q9: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 65°
length of the adjacent side to the angle = 9
length of the opposite side to the angle = x
Calculations:
Using the SOH CAH TOA rules:
Hence,

               TangentФ = Opposite ÷ Adjacent

Substituting the values:

               tan65° = x ÷ 9

               2.1445 = x ÷ 9

                          x = 2.1445 × 9

                          x = 19.30 (rounded to the nearest hundredth)

Q10: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 51°
length of the adjacent side to the angle = x
Length of Hypoteneus = 70
Calculations:
Using the SOH CAH TOA rules:
Hence,

               CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

               Cos51° = x ÷ 70

              0.6293  = x ÷ 70

                          x = 0.6293 × 70

                          x = 44.05 (rounded to the nearest hundredth)

Q11: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 36°
length of the opposite side to the angle = 15
Length of Hypoteneus = x
Calculations:
Using the SOH CAH TOA rules:
Hence,

               CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

               Sine36° = 15 ÷ x

               0.5877  = 15 ÷ x

                          x = 15 ÷ 0.5877

                          x = 25.52 (rounded to the nearest hundredth)

Q12: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 60°
length of the adjacent side to the angle = x
length of the opposite side to the angle = 100

Calculations:
Using the SOH CAH TOA rules:

Hence,

               TangentФ = Opposite ÷ Adjacent

Substituting the values:

               tan65° = 100 ÷ x

               2.1445 = 100 ÷ x

                          x = 100 ÷ 2.1445

                          x = 46.63 (rounded to the nearest hundredth)

Q13: When a 25-ft ladder is leaned against a wall, it makes a 72° with the ground. How high up on wall does the ladder reach?

Solution: Given the shape attached, therefore, using the triangle given, we have:

The angle of elevation from the ground = 72°
length of the wall opposite to the angle = X
Length of ladder (Hypoteneus) = 25 feet

Calculations:
Using the SOH CAH TOA rules:
Hence,

               SineФ = Opposite ÷ Hypotenuse

Substituting the values:

               Sine72° = x ÷ 25

               0.9510  = x ÷ 25

                          x = 25 ÷ 0.9510

                          x = 23.77 (rounded to the nearest hundredth)


ANSWERS TO QUESTION 14 AND  15 ARE ATTACHED

7 0
3 years ago
Which type of voting is more common – retrospective or prospective? Why? When you have to pick a candidate to vote, do you vote
padilas [110]

Answer: Both approach

Explanation:

This boils down to opinion of the masses as individuals choices differ, as most voters combine both retrospective and prospective approach when selecting their choice candidate. Some judge based on past performance of the candidate; was he successful to handling projects and Co? while others choose based what the candidate is promising to fulfill when they get into office.

Although some persons are more confident on past success of a candidate, some others would love to see changes that come with the new candidate.

6 0
3 years ago
In Colombian high schools , students have to choose the track they want to be in because each track leads to specific kind of __
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B. Diploma 
<span>In Colombian high schools , students have to choose the track they want to be in because each track leads to specific kind of diploma. </span>
6 0
3 years ago
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