Answer:
y = -x - 2
Step-by-step explanation:
Find two points on the line
(0, -2)
(4, -6)
(Y2-Y1)/(X2-X1) = gradient of the line
Where (X1,Y1) = (0, -2) and (X2,Y2) = (4, -6)
(-6--2)/(4-0)
(-6+2)/4
(-4)/(4)
-1
Y = (-1)X + c
Substitute either set of coordinates in to find c.
(0, -2)
Y = (-1)X + c
-2 = (-1)0 + c
-2 = 0 + c
-2 = c
(4,-6)
Y = (-1)X + c
-6 = (-1)4 + c
-6 = -4 +c
-6 + 4 = c
-2 = c
Y = -X -2
Since opposite exterior angles are congruent I would plug in numbers for X till you find a number that goes into both and gets you the same product.
Answer:
Step-by-step explanation:
Part A
xf = xo + vo* t + 1/2 a*t^2 Subtract xo
xf - xo = 0*t + 1/2 a*t^2 multiply by 2
2(xf - xo) = at^2 divide by t^2
2(xf - xo ) / t^2 = a
Part B
Givens
xo =0
vo = 0
a = 10 m/s^2
xf = 120 m
Solution
xf = xo + vo* t + 1/2 a*t^2 Substitute the givens
120 = 0 + 0 + 1/2 * 10 * t^2 Multiply by 2
120*2 = 10* t^2
240 = 10*t^2 Divide by 10
240/10 = t^2
24 = t^2 take the square root of both sides.
√24 = √t^2
t = √24
t = √(2 * 2 * 2 * 3)
t = 2√6
B
1/4 = 8/3 * x
X = 8/12
X= 2/3
