The horizontal distance until the plan flies over the island is 2687.05 feet approximately.
<u>Solution:</u>
Given that, A plane at an altitude of 7000 ft is flying in the direction of an island
An angle of depression is 21 degree from the plane to the island
We have to find what is the horizontal distance until the plan flies over the island
The diagram is attached below
Assume as shown in the diagram
, now we can use the right angle triangle property
Hence, the distance between plane and point above island is 2687.05 feet approximately.
Answer:
Step-by-step explanation:
<u>Sum of n terms formula:</u>
<u>Solving for n</u>
- 3480 = 1/2n(9 + 165)
- 3480 = 87n
- n = 3480/87
- n = 40
9514 1404 393
Answer:
(b) (-5, 1)
(c) (5, -7)
(d) (9, -2)
Step-by-step explanation:
The coordinate differences between the given points are ...
(4, 2) -(0, -3) = (4, 5)
The length of the line segment between the points is √(4² +5²) = √41, so this is the side of the square, not a diagonal.
The other four points that could be corners of the square are these same distances, but at right angles. To get points at right angles, the distance values can be swapped, and one of them negated.
Two of the points could be ...
(4, 2) ± (5, -4) = (9, -2) or (-1, 6)
and the other two could be ...
(0, -3) ± (5, -4) = (5, -7) or (-5, 1)
The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.
<u>Interquartile Range: </u>
Given the Data -> First Quartile = 2, Third Quartile = 5
Interquartile Range = 5 - 2 = 3
<u>Range:</u> 8 - 1 = 7
<u>Variance: </u>
We start by determining the mean,
n = number of numbers in the set
Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.
5.3
<u>Standard Deviation</u>
We take the square root of the variance,
2.3
If you are not familiar with variance and standard deviation, just leave it.
Answer:
k=m/5
Step-by-step explanation:
explained in the attached pi
