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4 years ago

8

A sidewalk borders a rectangular play area. The play area measures 20 feet by 14 feet. The width of the sidewalk is 2 feet. What

is the perimeter of the outside border of the sidewalk?

1 answer:

steposvetlana [31]4 years ago

8 0

That is going to be the fromula of 20x14x2

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Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

Find a value for y for which the expression (1-y)(3-y)(6-y) has each given value

erik [133]

$\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=-70$

$\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=-70$

$\\ \tt\Rrightarrow y(2)(4)(7)=70$

$\\ \tt\Rrightarrow y(56)=70$

$\\ \tt\Rrightarrow y=\dfrac{70}{56}$

$\\ \tt\Rrightarrow y=\dfrac{5}{4}$

#2

$\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=120$

$\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=120$

$\\ \tt\Rrightarrow -y(2)(4)(7)=120$

$\\ \tt\Rrightarrow 56y=-120$

$\\ \tt\Rrightarrow y=\dfrac{-120}{56}$

$\\ \tt\Rrightarrow y=\dfrac{-15}{7}$

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$\frac{13}{2} 0$

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Answer:

with?

Step-by-step explanation:

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An example of a rational number is.

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A the Awnser is A It’s kinda easy but then not really but the Awnser is A ok

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