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2 years ago

When do we use d=(x2-x1)+(y2-y1)

Mathematics

1 answer:

stiks02 [169]2 years ago

8 0

Answer:

to find the distance between two points on a coordinate plane

Step-by-step explanation:

yes

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A rocket is launched at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+100t+3

Vikentia [17]

Answer:

see below

Step-by-step explanation:

h(t)=−4.9t2+100t+325.

The independent variable is the one that we change

t which is in seconds

The dependent variable is the result

h(t) which is in meters

4 0

3 years ago

Simplify this equation Thanks a lot!!!

den301095 [7]

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

$\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}$

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

$\bf\implies a^m \times b^m = (ab)^m$

Using this property , we have ,

$\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}$

This can be written as ,

$\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}$

Simplifying using ( a+b)(a-b) = a² - b² ,

$\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}$

Subtracting the numbers inside the brackets ,

$\rm\implies (-1)^{2n - 1 }$

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the power is odd .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

$\rm\implies\boxed{\quad \red{ -1 }\quad }$

Hence the required answer is (-1) .

4 0

3 years ago

(PLEASE HELP)

KiRa [710]

D 2,4,5 it should be ( 3,4,5 )

5 0

3 years ago

Read 2 more answers

(2x + 3)(5x2 - 2x - 1) = Ax3 + Bx2 + Cx + D. What are the values of B and C?

Sati [7]

Answer:

B = 11; C = -8

Step-by-step explanation:

When simplified I get 10x^3 + 11x^2 - 8x - 3

3 0

3 years ago

Can someone please help? (Year 9 Math) This question is on fractions. Please see picture attached (ex. 2a and b) please show met

Ierofanga [76]

for 2a, use the theorems of geometry and such to look at the area of the square as 16 squares total, then use the lengths and Sim/cos rule for the triangular area, then subtract and you have you shaded area.

8 0

3 years ago