The equation: 6r-3=45
6r=48
Answer: r=8
1. 175m^2
2. 289.7cm^2
3. 42.8in^2
4. 62.4in^2
5. 88ft^2
6. 308.8cm^2
For all of these problems, I used the formula:
SA = Area of the base + 1/2(Perimeter of the Base)(Slant Height)
The two lines are parallel.
When they work together, it takes John 1/x hours and it takes Brian 1/(x+15) hours to complete 1/4 of the model.
1/x + 1/( x+15 ) = 1/4 / · x ( x+15 )
x+15 + x = x ( x+15 ) /4 / · 4
8 x + 60 = x² + 15 x
x² + 15 x - 8 x - 60 = 0
x² + 7 x - 60 = 0
x² + 12 x - 5 x - 60 = 0
x · ( x + 12 ) - 5 ·( x+ 12 ) = 0
( x + 12 ) · ( x - 5 ) =0
x = - 12 ( not accepted ) or x = 5
The time taken by Brian: 5 + 15 = 20 hours
Answer:
x
=
e
y
+
3
−
4
Step-by-step explanation:
Algebra Examples
Popular Problems Algebra Find the Inverse y=e^(x+3)-4
y
=
e
x
+
3
−
4
Interchange the variables.
x
=
e
y
+
3
−
4
Solve for
y
.
Tap for fewer steps...
Since
y
is on the right side of the equation, switch the sides so it is on the left side of the equation.
e
y
+
3
−
4
=
x
Add
4
to both sides of the equation.
e
y
+
3
=
x
+
4
Take the natural logarithm of both sides of the equation to remove the variable from the exponent.
ln
(
e
y
+
3
)
=
ln
(
x
+
4
)
Use logarithm rules to move
y
+
3
out of the exponent.
(
y
+
3
)
ln
(
e
)
=
ln
(
x
+
4
)
The natural logarithm of
e
is
1
.
(
y
+
3
)
⋅
1
=
ln
(
x
+
4
)
Multiply
y
+
3
by
1
.
y
+
3
=
ln
(
x
+
4
)
Subtract
3
from both sides of the equation.
