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AysviL [449]
3 years ago
13

Christina paints canvases and sells the pieces at craft fairs. The function c(t) approximates how many canvases she paints per h

our. The function w(h) represents how many hours per week Christina spends painting the canvases. What are the units of measurement for the composite function c(w(h))?
hours over weeks
weeks over canvases
canvases over weeks
canvases over hours
Mathematics
1 answer:
dsp733 years ago
7 0

Answer:

The units of measurement for the composite function c(w(h)) is canvases over weeks.

Step-by-step explanation:

Given :

The function c(t) approximates how many canvases she paints per hour.

The function w(h) represents how many hours per week Christina spends painting the canvases.

To Find: What are the units of measurement for the composite function c(w(h))?

Solution:

C(t)= canvases paints per hour

W(h)=hours per week

C(w(h)) =canvases paints per hour * hours per week

C(w(h)) =canvases per week

So, Option 3 is true

Hence , the units of measurement for the composite function c(w(h)) is canvases over weeks.

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0.004

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Since 4/10 is 0.4 and 4/100 is 0.04, 4/1000 must be 0.004

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9.2

Step-by-step explanation:

The given triangle is a right angled triangle. To solve for any of the side length of such triangle, apply the trigonometry ratio formula which can easily be remembered as SOHCAHTOA.

SOH is Sin θ = opposite/hypothenuse,

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TOA is Tan θ = Opposite/adjacent

Thus, in the right triangle given, we have:

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Find the solution to this system of equations <br> 3x+2y+3z=3 4x-5y+7z=1 2x+3y-2z=6 <br> x=? Y=? Z=?
Ede4ka [16]

Answer:

The solution is x=2,\ y=0,\ z=-1.

Step-by-step explanation:

You are given the system of three equations:

\left\{\begin{array}{l}3x+2y+3z=3\\4x-5y+7z=1\\2x+3y-2z=6\end{array}\right.

Multiply the first equation by 4, the second equation by 3 and subtract them. Then multiply the third equation by 2 and subtract it from the second equation:

\left\{\begin{array}{l}3x+2y+3z=3\\4(3x+2y+3z)-3(4x-5y+7z)=4\cdot 3-3\cdot 1\\4x-5y+7z-2(2x+3y-2z)=1-2\cdot 6\end{array}\right.\Rightarrow \\\\\left\{\begin{array}{l}3x+2y+3z=3\\12x+8y+12z-12x+15y-21z=12-3\\4x-5y+7z-4x-6y+4z=1-12\end{array}\right.

So,

\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\-11y+11z=-11\end{array}\right.\Rightarrow \left\{\begin{array}{l}3x+2y+3z=3\\23y-9z=9\\y-z=1\end{array}\right.

Multiply the third equation by 23 and subtract it from the second equation:

\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\23y-9z-23(y-z)=9-23\cdot 1\end{array}\right.\Rightarrow \left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\23y-9z-23y+23z=9-23 \end{array}\right.

Hence,

\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\14z=-14 \end{array}\right.\Rightarrow z=-1

Substitute it into the second equation:

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Substitute them into the first equation:

3x+2\cdot 0+3\cdot (-1)=3\Rightarrow 3x-3=3\\ \\3x=6\\ \\x=2

The solution is x=2,\ y=0,\ z=-1.

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