Answer:
3/2 g.oogle if you want the explanation of your work.
Answer:
3, in both a), b)
Step-by-step explanation:
a) The slope of the line tangent to the curve that passes through the point (2,-10) is equal to the derivative of p at x=2.
Using differentiation rules (power rule and sum rule), the derivative of p(x) for any x is
. In particular, the value we are looking for is
.
If you would like to compute the equation of the tangent line, we can use the point-slope equation to get ![y=3(x-2)-10=3x-16](https://tex.z-dn.net/?f=y%3D3%28x-2%29-10%3D3x-16)
b) The instantaneus rate of change is also equal to the derivative of P at the point x=2, that is, P'(2). This is equal to
.
I used a app, I also assumed that the “2x2” of the equation meant 2x^2
To work out radius use this