Answer: Bradley is
times as heavy as Ricardo.
Step-by-step explanation:
Given : The weight of Bradley = 207 pounds
The weight of Ricardo = 185 pounds
To find : Bradley is how many times as heavy as Ricardo?
For this , we divide "weight of Bradley " by "weight of Ricardo" , we get

Since 207 and 185 have no common factors , so it is the simplified way .
Further , we can convert it into mixed fraction as : 
Hence, Bradley is
times as heavy as Ricardo.
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Step-by-step explanation:
∆PQR similar to ∆ JKL
JK/KL= PQ/QR
6/12=3/QR
QR=3×2= 6
therefore, tan(R) = PQ/QR = 3/6=1/2
and, tan(J) = KL/JK =12/6=2


tan(J)=4.tan(R)
option D
Answer:
Error:
not 
Solution:x=0 and 3
Step-by-step explanation:
We have to find the error and correct answer
Given:![2ln x=ln(3x)-[ln9-2ln(3)]](https://tex.z-dn.net/?f=2ln%20x%3Dln%283x%29-%5Bln9-2ln%283%29%5D)
![lnx^2=ln(3x)-[ln9-ln3^2]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln3%5E2%5D)
Using the formula

![lnx^2=ln(3x)-[ln9-ln9]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln9%5D)





Therefore, x=0 and x=3
But last step in the given solution

It is wrong this property is used when
then

Hence, the student wrote
instead of
and solution is given by
x=0 and x=3
1/2 pieces of the hole because you can simplify 2/4 by dividing it by 2 and you'll get 1/2