Whats the answer to this problems

In the given image, m∠FBH = 88° and m∠FBG = 24°. If m∠GBH = 6x + 16°, what is the value of x?

Marysya12 [62]

Answer:

A. 8

Step-by-step explanation:

88° = [24]° + [6x + 16]°

88° = 40° + 6x°

-40° -40°

_______________

48 = 6x°

___ ___

6 6

8° = x

I am joyous to assist you anytime.

5 0

3 years ago

Aisha made bracelets for a craft fair. She spent $29.75 on supplies to make the bracelets. Each bracelet cost her about $0.85 to

Alchen [17]

Amount of money Aisha receive from selling all of the bracelets is $33.25.

<u>Step-by-step explanation:</u>

In this question, its given that Aisha made bracelets for a craft fair. She spent $29.75 on supplies to make the bracelets. Each bracelet cost her about $0.85 to make. Aisha sells each bracelet for $0.10 more than it cost her to make. Let's calculate Number of bracelets Aisha made as $\frac{total-cost}{cost-of-one-bracelet}$ .

Number = $\frac{total-cost}{cost-of-one-bracelet}$

⇒ Number = $\frac{total-cost}{cost-of-one-bracelet}$

⇒ Number = $\frac{29.75}{0.85}$

⇒ Number = $35$

Now , its given that Aisha sell these bracelets with $0.10 more then it cost her i.e. at $0.95 , Let's calculate selling price as :

Price = $0.95(35)$

Price = $33.25

Therefore, amount of money Aisha receive from selling all of the bracelets is $33.25.

4 0

4 years ago

Last year, the price of a 45-ounce box of detergent was $3.75. This year, the price of a 45-ounce box of detergent is $4.50. Wha

Romashka-Z-Leto [24]

First, we need to find out how much the price increased by.

$4.50 - $3.75 = $0.75

Now we have to figure out what percent $0.75 is of $3.75. To do this, we divide $0.75 by $3.75.

The answer is 0.2. Now, we convert this into a percent by moving the decimal to the right by to spaces: 0.2 = 20%

The percent of increase is 20%.

4 0

4 years ago

Read 2 more answers

10,000 round to the nearest ten thousand

wlad13 [49]

Answer:

i think it would be 10,000

I hope it helped!

5 0

3 years ago

Read 2 more answers

Solve each equation (Polynomial equations)

lesya [120]

${ {e}^{x} }^{2} = \frac{1}{ {e}^{2} } \times {e}^{3x} \\ \Leftrightarrow { {e}^{x} }^{2} = {e}^{ 3x} \times {e}^{ - 2} \\ \Leftrightarrow { {e}^{x} }^{2} = {e}^{3x - 2} \\ \Leftrightarrow {x}^{2} = 3x - 2 \\ \Leftrightarrow {x}^{2} - 3x + 2 = 0 \\ \Leftrightarrow (x - 1)(x - 2) = 0 \\ x = 1 \: \vee \: x = 2 \\ \\ {32}^{ {x}^{2} - 2x } = \frac{1}{ {4}^{x} } \\ \Leftrightarrow {( {2}^{5} )}^{ {x}^{2} - 2x } = {2}^{ - 2x} \\ \Leftrightarrow {2}^{5 {x}^{2} - 10x } = {2}^{ - 2x} \\ \Leftrightarrow 5 {x}^{2} - 10x = - 2x \\ \Leftrightarrow 5 {x}^{2} - 8x = 0 \\ \Leftrightarrow x(5x - 8) = 0 \\ \Leftrightarrow x = 0 \: \vee \: x = \frac{8}{5} \\ \\ { {e}^{x} }^{3} = {2}^{2x} \\ \Leftrightarrow {x}^{3} = ln( {2}^{2x} ) \\ \Leftrightarrow {x}^{3} - 2x ln(2) = 0 \\ \Leftrightarrow x( {x}^{2} - 2 ln(2) ) = 0 \\ \Leftrightarrow x = 0 \:\vee \: {x}^{2} = 2 ln(2) \\ \Leftrightarrow x = 0 \:\vee \: x = \sqrt{2 ln(2) } \:\vee \: x = - \sqrt{2 ln(2) }$

8 0

4 years ago